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kolezko [41]
3 years ago
14

Determine the intercepts of the line. y=-73 +3 y-intercept: x-intercept:

Mathematics
2 answers:
BaLLatris [955]3 years ago
8 0

Answer:

y =  - 7x + 3 \\ for \: y - intercept, \: x = 0 \\ y = ( - 7 \times 0) + 3 \\ y = 3 \\ y - intercept \: is \: (0,3) \\ for \: x - intercept, \: y = 0 \\ 0 =  - 7x + 3 \\  - 7x =  - 3 \\ x =  \frac{3}{7}  \\ x - intercept \: is \: ( \frac{3}{7} ,0)

Allushta [10]3 years ago
5 0

Answer:

  • y = - 7x + 3
  • For y - intercept, x = 0

y = ( - 7 ×0) + 3

<u>y = 3 </u>

y - intercept is (0,3)

  • For x - intercept, y = 0

0 = - 7x + 3

- 7x = - 3

x<u> = 3/7</u>

x - intercept is (3/7 ,0)

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One cubic meter of water weighs approximately 2200 pounds. There are 100 cm in one meter. If you have a box-shaped fish tank tha
Diano4ka-milaya [45]

Answer:

158.4 pounds

Step-by-step explanation:

first find the volume of the tank

V = 30 \times 30 \times 80

V = 72000 cm^3

to convert this to m^3 we know that 1m = 100cm

V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}}{100\,\text{cm}}\right)^3

V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}^3}{100^3\,\text{cm}^3}\right)

the cm^3 cancel out.

V = \dfrac{72000}{100^3} m^3

V = 0.072\,m^3

by simply converting the side-lengths to meters beforehand can give you this answer directly:

V = 0.3 \times 0.3 \times 0.8 = 0.072 m^3

it is given that 1 meter cube of water weighs about 2200 pounds.

1\,m^3 = 2200 \,\text{lb}

multiply both sides with 0.072 to find our answer:

1\,m^3 \times 0.072 = 2200 \times 0.072 \,\text{lb}

0.072\,m^3 = 158.4 \,\text{lb}

hence the weight of the water in the tank would be 158.4 pounds!

3 0
3 years ago
Given the function f(x)=|x|,describe the transformation lys to f(x)=|x-2|+5
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C is the correct answer
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Help with this proof
mixer [17]
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Feel free to ask further questions! 
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Answer:

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Step-by-step explanation:

This is because 4 is less than  10 and 10 is greater than 4, making them overlap

4 0
3 years ago
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