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1 year ago

I need help with my math

1 answer:

6 0

In order to determine the temperature at 11:00 pm, consider that at that time the temperature reduces 5 degrees related to the temperature at 6:00 pm.

Then, subtract 5 to the temaperature at 6:00 pm, which is 5°F:

5°F - 5°F = 0°F

Hence, the temperature at 11:00 pm is 0°F

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The performance review scores for several employees in a work group are shown in the table. Which of the following measures woul

german

If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way greater it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).

8 0

3 years ago

Two angles are supplementary. One angle is 5degrees° more than six times the other. Find the measure of each angle.

kolbaska11 [484]

Well do you know what a supplementary angles is ?
it is two angles that add up to 180 degrees

6 0

2 years ago

Identify the perimeter and area of a square with diagonal length 11in. Give your answer in simplest radical form. HELP PLEASE!!

Nataliya [291]

Answer:

Perimeter = 22*sqrt(2)
Area = 60.5 inches
D

Step-by-step explanation:

Remark

You need 2 facts.

A square has 4 equal sides.
It contains (by definition) 1 right angle but since we are not including and statement about parallel sides, it needs 4 right angles.

That means you can use the Pythagorean Theorem.

If one side of a square is a then the 1 after it is a as well.

Formula

a^2 + a^2 = c^2
2a^2 = c^2

Givens

c = 11

Solution

2a^2 = 11^2
2a^2 = 121 Divide by 2
a^2 = 121/2 Take the square root of both sides
sqrt(a^2) = sqr(121/2)
a = 11/sqrt(2) Rationalize the denominator
a = 11 * sqrt(2)/[sqrt(2) * sqrt(2)]
a = 11 * sqrt(2) / 2

Perimeter

P = 4s

P = 4*11*sqrt(2)/2
P = 44*sqrt(2)/2
P = 22*sqrt(2)

You don't need the area. The answer is D

Area

Area = s^2
Area = (11*sqrt(2)/2 ) ^2
Area = 121 * 2 / 4
Area = 60.5

8 0

2 years ago

How do you solve this? Please help

Pie

Wbertkdiwrjrjjwjwj !!!

6 0

3 years ago

Which statement describes the translation of y = −one half (x − 2)2 − 2 from standard position?

kaheart [24]

A quadratic in vertex form can be represented as

$y = a(x-h)^{2} +k$

a represents reflection over the x-axis, and a vertical stretch or compress
- is reflection and a fraction (1/2) represents a compression.

-h represents a shift of that many units to the right (-2 shifts to the right two units)

k represents a shift up or down (-2 is shifting down 2 units_

Reflected over the x-axis, Vertically compressed by a factor of 1/2, shifted 2 units to the right, and shifted 2 units down

5 0

2 years ago