Answer:
0.03865
Step-by-step explanation:
Since the true density for the two types of trees are given, we would evaluate the average for both of them
Low percentage of juvenile wood density = 0.523 and 0.0543
Average density = 0.523 + 0.0543/2
Average density = 0.55015
Moderate percentage of juvenile wood density = 0.489 and 0.0450
Average density = 0.489 + 0.0450/2
Average density = 0.5115
Therefore, difference in true average density for the two woods are = 0.55015 - 0.51150
= 0.03865
Okay I did the work and I think it’s either answer a or b but goodluck sorry
But I still don’t understand this.
The answer to the problem is y=-13
X = 1st job
y = 2nd job
x + y = 22......x = 22 - y
7x + 8.25y = 171.50
7(22 - y ) + 8.25y = 171.50
154 - 7y + 8.25y = 171.50
-7y + 8.25y = 171.50 - 154
1.25y = 17.50
y = 17.50 / 1.25
y = 14 <== 14 hrs at the 8.25 per hr job
x + y = 22
x + 14 = 22
x = 22 - 14
x = 8 <=== 8 hrs at the 7 per hr job
Answer:
A. E cannot affect F and vice versa because the people were randomly selected, so the events are independent.
Step-by-step explanation:
Imagine a situation.
We probably live very far from each other
There is a probability that I kill a spider.
There is a probability that you accidentaly swallows a spider.
Or vice-versa.
If I kill a spider, i won't impact the probability that you accidentaly swallows a spider. So these events are independent, and the correct answer is:
A. E cannot affect F and vice versa because the people were randomly selected, so the events are independent.
