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kakasveta [241]
3 years ago
7

Write 2x+3y=6 in slope-intercept form. ahhhh i need help stat

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
5 0
That’s the answer your welcome

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Solve using the multiplication principle. Don't forget to perfom a check<br> -3/5x = 6/35
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Hi! -3/7 X -2/7 equals 6/35

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I hope this helps you, Goodluck :)
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Note: Triangle may not be drawn to scale.
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Step-by-step explanation:

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Write two division expressions that have the same value as 36.8 divided by 2.3 (16)
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144 divided by 9=16

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Use the GCF to factor 8-6
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Phyllis invested $11,500, a portion earning a simple interest rate of
Cerrena [4.2K]

Answer:

He invested $8500 with rate 3 1/5%

He invested $3000 with rate 3%

Step-by-step explanation:

* <em>Lets revise the rule of the simple interest</em>

- Simple interest I = PRT, where P in the money invested, R is the

 interest rate and T is the time of investment

- Phyllis invested $11,500

- A portion earning a simple interest rate of 3 1/5% (3.2%) per year

- The rest earning a rate of 3% per year

- After one year the total interest earned on these investments

 was $362.00

- We need to find the amount of money invested in each rate

* Assume that he invested $x with rate 3 1/5% and $y with rate 3%

∵ He invested $11,500 in both rates

∴ x + y = 11,500 ⇒ (1)

∵ He invested $x with 3 1/5%

∵ P = $x

∵ R = 3.2/100 = 0.032

∵ T = 1

∴ I_{1}=x(0.032)(1)

∴ I_{1}=0.032x

∵ He invested $y with 3%

∵ P = $y

∵ R = 3/100 = 0.03

∵ T = 1

∴ I_{2}=y(0.03)(1)

∴ I_{2}=0.03y

∵ The total interest was $362.00

- The total interest = I_{1} + I_{2}

∴ 0.032x + 0.03y = 362.00 ⇒ (2)

<em>We have system of equations</em>

x + y = 11,500 ⇒ (1)

0.032x + 0.03y = 362.00 ⇒ (2)

Multiply equation (1) by -0.03 to eliminate y

-0.03x - 0.03y = 345 ⇒ (3)

Add equations (2) and (3)

0.002x = 17

Divide both sides by 0.002

x = 8500

Substitute the value of x in equation (1)

8500 + y = 11,500

Subtract 8500 from both sides

y = 3000

* He invested $8500 with rate 3 1/5%

* He invested $3000 with rate 3%

7 0
3 years ago
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