All categories

3 years ago

I will give brainliest and thank you to whoever helps/answers this

Mathematics

1 answer:

Neko [114]3 years ago

5 0

Answer:

0 0 6

0 6 0

6 0 0

Step-by-step explanation:

Simple place value

You might be interested in

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

2 years ago

For the given function, x can have what value?

Lyrx [107]

Answer:

x cannot be -4,-3, or 13

x can be anything else

Step-by-step explanation:

There are infinitely many values x can take where the relation above will be a function.

For it to be a function, you just need to make sure each x is only assigned one y value.

So x couldn't be -4 because it would by assigned to y=2 and y=0.

x couldn't be -3 because it would be assigned to y=1 and y=0.

x couldn't be 13 because it would be assigned to y=5 and y=0.

So as long as x is not chosen to be -4,-3, or 13 your relation here is a function.

5 0

3 years ago

Through (4,-4) ; perpendicular to 6y=x-12

BARSIC [14]

y = mx + b

m = slope and b = y-intercept

We can arrange 6y = x - 12 in the form of y = mx + b

6y = x - 12

y = 1/6(x) - 2

Slope of y = 1/6(x) - 2 is 1/6. Taking the negative reciprocal of the slope we get the slope for the perpendicular line.

Negative reciprocal of 1/6 is -6.

The equation for the perpendicular line is

y = -6x + b

To find b we can plug in the x and y values of (4,-4) into it since it passes through those coordinates

-4 = -6(4) + b

b = -4 + 6(4)

b = -4 + 24

b = 20

So the equation for the perpendicular line is y = -6x + 20

3 0

3 years ago

X=-4 +6+ (11 +4(-3))

lapo4ka [179]

Answer:

x=1

Step-by-step explanation:

x = -4 + 6 + (11 + 4(-3)).

First get the numbers in the parentheses

x = -4 + 6 + (11 - 12)

Since 11 - 12 = -1. We can replace (11-12) with -1

x = -4 + 6 -1

Now add and subtract

x = 1

4 0

2 years ago

Write -12 in the improper fraction form.

nydimaria [60]

Answer:

$\frac{-12}{1}$

Step-by-step explanation:

An Improper Fraction has a top number larger than (or equal to) the bottom number.

To convert a whole number -12 into an improper fraction we can divide the whole number by one to turn it into a temporary fraction.

$\frac{-12}{1}$

Also we could multiply and divide -12 by another number greater than one, for example:

$\frac{-12*2}{1*2} = \frac{-24}{2}$

There are several ways we can write -12 in the improper fraction form.

6 0

3 years ago