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xz_007 [3.2K]
3 years ago
10

I will give brainliest and thank you to whoever helps/answers this

Mathematics
1 answer:
Neko [114]3 years ago
5 0

Answer:

0 0 6

0 6 0

6 0 0

Step-by-step explanation:

Simple place value

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Would anyone help me with this,please ?
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Answer:

angle 2 and 4....1and 3

Step-by-step explanation:

the lines bisects each other forming two equal but adjacent angles which are vertically opposite

8 0
3 years ago
Factor the expression <br> 36x + 27 using the GCF.
laila [671]

Answer:

9(4x+3)     :)

Step-by-step explanation:

4 0
3 years ago
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3 0
3 years ago
The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha
Xelga [282]

Answer:

The average value of f over the interval [-2,5] is \frac{10}{7}.

Step-by-step explanation:

Let suppose that function f is continuous and integrable in the given intervals, by integral definition of average we have that:

\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6 (1)

\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20 (2)

By Fundamental Theorems of Calculus we expand both expressions:

\frac{F(3)-F(-2)}{3-(-2)} = -6

F(3) - F(-2) = -30 (1b)

\frac{F(5)-F(3)}{5-3} = 20

F(5) - F(3) = 40 (2b)

We obtain the average value of f over the interval [-2, 5] by algebraic handling:

F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)

F(5) - F(-2) = 10

\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}

\bar f = \frac{10}{7}

The average value of f over the interval [-2,5] is \frac{10}{7}.

4 0
2 years ago
What is the volume of a shoe box with length 13 inches, width 7 inches, and height 5 inches? V = lwh in3
Sati [7]
The volume is 13*7*5. Therefore, the answer is 455 in^3
4 0
3 years ago
Read 2 more answers
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