Let X be the first number
there is a 2 numbers distance between each even number eg.2 ,4, 6, 8, etc.
So the 2nd number is X+2
The sum of the 1st and 2nd numbers = 14
X + X+2 =14
2X +2 =14
2X = 14-2
2X = 12
X = 12/2
X = 6
Therefore,
The first number i.e, X = 6
And the second number i.e, X+2 = 6+2 =8
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This is the only positive pair in case of two consecutive numbers if the are even numbers but not consecutive there will be more pairs
12 + 2 = 14
10 + 4 = 14
8 + 6 = 14 (Already found)
I have taken the test and I can confirm that the answer is
B. 15 m, 20 m, and 25 m.
Have a fantastic day!
Answer:
x=(10-k)÷6
Step-by-step explanation:
6x=10-k
x=(10-k)÷6
Answer:
you are subtracting 1.40 everytime to get the number at the bottom
Step-by-step explanation:
2 - 1.40 = 1.40
3 - 1.40 = 2.40
6 - 1.40 = 5.40
7 - 1.40 = 6.40
The distance around a circle
Hope this helped ;)
