Answer:
The fraction of wood used for horizontal support is 
.
Step-by-step explanation:
Assume that the total piece of wood is of length 1.
It is provided that Talia used 
of the piece of wood for the base of he project.
She use 
of the piece of wood for the for the vertical support.
The remaining wood she used for horizontal support.
The amount of wood used for horizontal support can be computed by the subtracting the amount of wood used for base of the project and vertical support form 1.
Compute the amount of wood used for horizontal support as follows:
Thus, the fraction of wood used for horizontal support is .
Answer:
...............
Step-by-step explanation:
1. Let's solve your equation step-by-step.
<span><span><span>4x</span>+5</span>=<span>6x
</span></span>Step 1: Subtract 6x from both sides.
<span><span><span><span>4x</span>+5</span>−<span>6x</span></span>=<span><span>6x</span>−<span>6x
</span></span></span><span><span><span>−<span>2x</span></span>+5</span>=0
</span>Step 2: Subtract 5 from both sides.
<span><span><span><span>−<span>2x</span></span>+5</span>−5</span>=<span>0−5
</span></span><span><span>−<span>2x</span></span>=<span>−5
</span></span>Step 3: Divide both sides by -2.
<span><span><span>−<span>2x/</span></span><span>−2 </span></span>=<span><span>−5/</span><span>−2
</span></span></span><span><span>
</span></span>Answer:<span>x=<span>5/<span>2</span></span></span>
A -3 subtracted by 10 is -13 and it stays 2
Answer:
1.) There are 16 juniors and 8 seniors in the Chess Club. If the club members decide to send 9 juniors to a tournament, how many different possibilities are there?
(16 over 9) = 16!/(9!*7!) = 11440
2.) How many different ways can 3 cards be drawn from a deck of 52 cards without replacement?
52*51*50 = 132600
3.) How many different ways can 3 cards be drawn from a deck of 52 cards with replacement?
52^3 = 140608
4.) A corporation has 5 officers to choose from which 3 are selected to comprise the board of directors. How many combinations are there?
(5 over 3) = 5!/(3! * 2!) = 10
5.) A combination lock has the numbers 1 to 40 on each of three consecutive tumblers. What is the probability of opening the lock in ten tries?
10/40^3 = 1/6400
