Qué número tiene el valor que 14 decenas

A group of 54 college students from a certain liberal arts college were randomly sampled and asked about the number of alcoholic

Ket [755]

Answer:

$t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601$

P-value

First we find the degrees of freedom given by:

$df = n-1= 54-1=53$

Since is a two-sided test the p value would be:

$p_v =2*P(t_{53}>0.9601)=0.3414$

Step-by-step explanation:

Data given and notation

$\bar X=5.25$ represent the sample mean

$s=3.98$ represent the sample standard deviation

$n=54$ sample size

$\mu_o =4.73$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean differs from 4.73, the system of hypothesis would be:

Null hypothesis: $\mu =4.73$

Alternative hypothesis: $\mu \neq 4.73$

Since we know don't the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601$

P-value

First we find the degrees of freedom given by:

$df = n-1= 54-1=53$

Since is a two-sided test the p value would be:

$p_v =2*P(t_{53}>0.9601)=0.3414$

7 0

3 years ago

In 2012, about 24% of high-school seniors reported binge drinking (defined as five or more drinks in a row in the past two weeks

Artist 52 [7]

Answer: (0.24 - 1.96*0.019, 0.24 + 1.96*0.019)

Step-by-step explanation:

We know that the confidence interval population proportion (p) is given by :-

$\hat{p}\pm z*\cdot SE$

, where $\hat{p}$ = sample proportion.

z* = Critical value (Two -tailed)

SE = standard error

Given : In 2012, about 24% of high-school seniors reported binge drinking (defined as five or more drinks in a row in the past two weeks), a substantial drop since the late 1990s.

$\hat{p}=0.24$

SE = 0.019

Significance level = $\alpha=1-0.95=0.05$

Two-tailed value corresponds for $\alpha=0.05$ :

z*=1.96 [Using z-table]

Now, the 95% confidence interval for the proportion of high-school seniors in the sample who would report binge drinking will be :-

$0.24\pm (1.96)\cdot (0.019)=(0.24-1.96\times 0.019,\ 0.24+1.96\times 0.019)$

Hence, the correct answer = (0.24 - 1.96*0.019, 0.24 + 1.96*0.019)

8 0

3 years ago

What should I make sure to remember about a variable with no coefficient?

ICE Princess25 [194]

A variable with no coefficient...

Do you mean something like 'x'

The coefficient is 1 because x=1x

Best of luck!

4 0

2 years ago

Assume that the number of defective basketballs produced is related by a linear equation to the total number produced. Suppose t

sveta [45]

Answer: 22 defective balls

Step-by-step explanation:

Using the law of equality,

9 defective balls = 225 ...eqn 1.

14 defective balls = 350...eqn 2

x defective balls = 550...eqn 3

We can use any two of the equations above to get the unknown variable 'x'

Using equations 2 and 3,

14 defective balls = 350...eqn 2

x defective balls = 550...eqn 3

We cross multiply to have

x×350 = 14×550

Dividing both sides by 350,

x = 14×550/350

x = 22.

Therefore, the number of defective balls produced in a lot of 550 balls are 22balls.

Note that we will still arrive at the same answer (22balls) if equation 1 and 3 are used for our solution.

Thank you!

8 0

2 years ago

If a1=4 and an= 3an-1 then find the value of a6.

Romashka [77]

Answer:

a₆ = 972

Step-by-step explanation:

Given a₁ = 4 and $a_{n}$ = 3 $a_{n-1}$ , then

a₂ = 3a₁ = 3 × 4 = 12

a₃ = 3a₂ = 3 × 12 = 36

a₄ = 3a₃ = 3 × 36 = 108

a₅ = 3a₄ = 3 × 108 = 324

a₆ = 3a₅ = 3 × 324 = 972

4 0

2 years ago

Qué número tiene el valor que 14 decenas￼

Qué número tiene el valor que 14 decenas