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Leviafan [203]
3 years ago
12

Explain how you could use objects to act out this problem

Mathematics
2 answers:
hjlf3 years ago
7 0
Multiply the first number givin
romanna [79]3 years ago
5 0
By using the first number mulitiply
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Mary takes 9 grapes from rohin and then decides to give 4 back draw a model for the subtraction problem using integer chips
kaheart [24]

That should be correct

3 0
3 years ago
What is the area of a triangle with a height of 13 cm and a base of a 10 cm?
Alecsey [184]
Area of a triangle is equal to 1/2 b(h) so since you already have the height and base, all you need to do is input it back into the equation:

\frac{1}{2} (10)(13)


Multiply 10 & 13 to equal 

\frac{1}{2} (130)

Then take half of 130 to get

A = 65 cm^{2}
8 0
3 years ago
Read 2 more answers
Where are the minimum and maximum values for f(x) = -2 + 4 cos x on the interval (0,21]?
Dafna11 [192]

Answer:

Step-by-step explanation:

Maximum value is when cos x = 1

So it is -2 + 4(1) = 2.

Minimum value, when  cos x = -1:

= -2  + 4(-1) = -6.

4 0
3 years ago
Read 2 more answers
O perimetro de uma praça é 320 m. Qual o valor do seu diâmetro
never [62]

Answer:

A área de um quadrado cujo perímetro é de 320 m é 6400 m2

Step-by-step explanation:

4 0
3 years ago
What is a formula for the nth term of the given sequence? 48, 72, 108​
WITCHER [35]

Answer:

a_n=48*1.5^{n-1}

Step-by-step explanation:

<u>Geometric Sequence</u>

In geometric sequences, each term is found by multiplying (or dividing) the previous term by a fixed number, called the common ratio.

We are given the sequence:

48, 72, 108, ...

The common ratio is found by dividing the second term by the first term:

r=\frac{72}{48}=1.5

To ensure this is a geometric sequence, we use the ratio just calculated to find the third term a3=72*1.5=108.

Now we are sure this is a geometric sequence, we use the general term formula:

a_n=a_1*r^{n-1}

Where a1=48 and r=1.5

\boxed{a_n=48*1.5^{n-1}}

For example, to find the 5th term:

a_5=48*1.5^{5-1}=48*1.5^{4}=243

7 0
3 years ago
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