Answer:
we can not reject any value
Step-by-step explanation: From data we can test the highest and the lowest value to evaluate if one of these values are out of certain confidence Interval
If we established CI = 95 % then α = 5 % and α/2 = 0,025
From data we find the mean of the values
μ₀ = 12,03 and σ = 0,07
From z table we find z score for 0,025 is z(c) = ± 1,96
So limits of our CI are:
12,03 + 1,96 = 13,99
12,03 - 1,96 = 10,07
And all our values are within ( 10,07 , 13,99)
So we can not reject any value
Answer:
12 students
Step-by-step explanation:
Given
Required
Determine the number of students that eat lunch once a week
In Sets;
If out of 9, at least 7 eats one a week then
9 - 7 eats lunch once a week
<em>In other words;</em>
2 out of 9 students eat lunch once a week
Number of students in this category is then calculated as thus;
Yeah dang i have no idea. great question tho
Answer:
2
Step-by-step explanation:
as H=20 and W=10
So H=constant.(W)
H=2(10)
H=20
So constant is 2
