Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDLcholesterol?
sample mean = x-bar = 4.7
ME = 1.96*15.6/sqrt(43) = 4.663
95% CI: 4.7 - 4.663 < u < 4.7 + 4.663
The answer is 200,000. The reason why is because 50000*4=200,000
Answer:
the answer you are looking for is C
45.864, because 57.33 divided by 100 is 0.5733 that multiplied by 80 is 45.864
