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3 years ago

Help me please answer thanks please don’t put random stuff

Mathematics

1 answer:

ipn [44]3 years ago

8 0

Answer:

what is the question

Step-by-step explanation:

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200 points if you answer my question i posted or maybe 100 i really dont know plz help me

KonstantinChe [14]

Answer:

I'll see if I could help.

Step-by-step explanation:

8 0

3 years ago

A store has been selling 300 Blu-ray disc players a week at $600 each. A market survey indicates that for each $40 rebate offere

timurjin [86]

Answer:

75 $

Step-by-step explanation:

According to problem statement p(300) = 600

And we know that with a rebate of 40 $, numbers of units sold will increase by 80 then if x is number of units sold, the increase in units is

( x - 300 ) , and the price decrease

(1/80)*40 = 0,5

Then the demand function is:

D(x) = 600 - 0,5* ( x - 300 ) (1)

And revenue function is:

R(x) = x * (D(x) ⇒ R(x) = x* [ 600 - 0,5* ( x - 300 )]

R(x) = 600*x - 0,5*x * ( x - 300 )

R(x) = 600*x - 0,5*x² - 150*x

R(x) = 450*x - (1/2)*x²

Now taking derivatives on both sides of the equation we get

R´(x) = 450 - x

R´(x) = 0 ⇒ 450 - x = 0

x = 450 units

We can observe that for 0 < x < 450 R(x) > 0 then R(x) has a maximum for x = 450

Plugging this value in demand equation, we get the rebate for maximize revenue

D(450) = 600 - 0,5* ( x - 300 )

D(450) = 600 - 225 + 150

D(450) =

D(450) = 600 - 0,5*( 150)

D(450) = 600 - 75

D(450) = 525

And the rebate must be

600 - 525 = 75 $

5 0

3 years ago

Which expression is equal to 4^5 x 4^-7 divided by 4^-2

Mars2501 [29]

This is not my level but i can try to solve it

3 0

4 years ago

Which shows the terms of the series? 4 12 48 192 4 12 36 3 12 48 192 3 12 48

Stells [14]

The value of the term in the series will be equal to 3 + 12 +48 + 192 after calculation.

<h3>What is summation?</h3>

In mathematics, the summation is the addition of a sequence of any kind of numbers, called addends or summands.

Now we have a given term

$\sum_{n=1}^{4} 3(4)^{n-1}$

By solving the above term;

$\sum_{n=1}^{4} 3(4)^{n-1}=3(4)^{1-1}+3(4)^{2-1}+3(4)^{3-1}+3(4)^{4-1}$

$\sum_{n=1}^{4} 3(4)^{n-1}=3(4)^0+3(4)^1+3(4)^2+3(4)^3$

$\sum_{n=1}^{4} 3(4)^{n-1}=3 + 12 +48 + 192$

Hence the value of the term in the series will be equal to 3 + 12 +48 + 192 after calculation.

To know more about Summation follow

brainly.com/question/2767605

5 0

2 years ago

Find the area of a parallelogram with a height of 2x - 3 and a base of x + 4.

saw5 [17]

Multiply the two as area is base times height.
$(2x - 3)(x + 4) \\ 2 {x}^{2} + 8x - 3x - 12 \\ 2 {x}^{2} + 5x - 12$

4 0

3 years ago