3 years ago

I need help please

Mathematics

1 answer:

Zina [86]3 years ago

8 0

Answer:

Its out of A and C srry couldn't help much

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What is the inverse of y=pi/2+sin x

Alekssandra [29.7K]

Answer:

$f^{-1}(x)=\sin ^{-1}(x-\frac{\pi}{2})$

Step-by-step explanation:

The given function is

$y=\frac{\pi}{2}+\sin x$

To find the inverse of this function, we interchange x and y.

$x=\frac{\pi}{2}+\sin y$

we now solve for y.

$x-\frac{\pi}{2}=\sin y$

Take the sine inverse of both sides to obtain;

$\sin ^{-1}(x-\frac{\pi}{2})=y$

Hence the inverse of the given function is;

$f^{-1}(x)=\sin ^{-1}(x-\frac{\pi}{2})$

where $\frac{\pi}{2}-1\le x\le \frac{\pi}{2}+1$

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$45.05

Step-by-step explanation:

53.00 × 0.85 = 45.05

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Step-by-step explanation:

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Find an ordered pair x-2y=4

Vesnalui [34]

Answer:

Step by Step:
x-2y=4
+2y +2y
x=-2y+4

x-2y=4
-4 -4
x-2y-4=0
+2y +2y
x-4=2y
Divid by 2
1/2x-2= y

x=-2y+4
x=-2(1/2x-2)+4
x=-x+4+4
x=-x+8
+x +x
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stiv31 [10]

Answer:

3(y+6)=30

3y + 18 = 30

18 - 30 = 3y

12 = 3y

12/3 = y

4 = y

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I need help please ​

I need help please