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3 years ago

Work out the percentage change to 2 decimal places when a price of £12 is increased to £15.99

Mathematics

1 answer:

NISA [10]3 years ago

6 0

Hence, the percentage increment is 33.25%

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What is 74 multiply by 65?

Nady [450]

That equals 4,810. Make sure to have a placeholder when you multiply

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3 years ago

mr zuro finds the man height of all 14 students in his statistics class to be 68 inches .just as mr zuro finishes explaining ho

mylen [45]

Add all 15 students' amounts: 14(68 inches), then add 65. Take the sum and divide it by 15 students, to get the mean. The answer is 67.8

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3 years ago

(WILL GIVE BRAINLIEST) Describe how you would simplify the given expression.

Vinil7 [7]

Answer:

Simplify inside the parentheses by dividing coefficients, subtracting the exponents on like bases, and raising the resulting expression to the –3 power. Then, write bases with positive exponents.

Raise the numerator and denominator to the –3 power. Then, using the power of a power property, multiply the exponents. Divide the coefficients and subtract the exponents on like bases, then write with positive exponents.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

which of the three sets could not be the lengths of the sides of a triangle {6,10,12} {5,7,10} {4,4,9} {2,3,3}

Phoenix [80]

So for this, we will be applying the Triangle Inequality Theorem, which states that the sum of 2 sides must be greater than the third side for it to be a triangle. If any inequality turns out to be false, then the set cannot be a triangle.

$A+B>C\\A+C>B\\B+C>A$

<h2>First Option: {6, 10, 12}</h2>

Let A = 6, B = 10, and C = 12:

$6+10>12\\16>12\ \textsf{true}\\\\6+12>10\\18>10\ \textsf{true}\\\\12+10>6\\22>6\ \textsf{true}$

<h2>Second Option: {5, 7, 10}</h2>

Let A = 5, B = 7, and C = 10

$5+7>10\\12>10\ \textsf{true}\\\\5+10>7\\15>7\ \textsf{true}\\\\10+7>5\\17>5\ \textsf{true}$

<h2>Third Option: {4, 4, 9}</h2>

Let A = 4, B = 4, and C = 9

$4+4>9\\8>9\ \textsf{false}\\\\4+9>4\\13>4\ \textsf{true}\\\\4+9>4\\13>4\ \textsf{true}$

<h2>Fourth Option: {2, 3, 3}</h2>

Let A = 2, B = 3, and C = 3

$2+3>3\\5>3\ \textsf{true}\\\\2+3>3\\5>3\ \textsf{true}\\\\3+3>2\\6>2\ \textsf{true}$

<h2>Conclusion:</h2>

Since the third option had an inequality that was false, <u>the third option cannot be a triangle.</u>

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3 years ago

Read 2 more answers

An Amazing Graph please answer it

dlinn [17]

No clue
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4 years ago