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2 years ago

What's the Lateral Surface Area? What's the Surface area

Mathematics

1 answer:

KengaRu [80]2 years ago

4 0

Answer:

The lateral surface of an object is all of the sides of the object , except/excluding its base and top.

I think I am correct I might sure I read it somewhere

by this explanation I guess you know your answer

have a nice day

#Captainpower

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Distance between (7,-1) and (),3)

Art [367]

Answer:

Step-by-step explanation:

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2 years ago

If the area of the right triangle is 72 what is the value of x

wel

36 i guess ha please that not right

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3 years ago

Tim has $250 in his account. This is $75 more than his brother Nate has in his account. Write and solve an addition equation to

BaLLatris [955]

Answer: 250+75

Step-by-step explanation:

250+75= 325

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2 years ago

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Square ABCD is shown with four congruent images such that ABCD FGHI JKLM NOPQ RSTU.

N76 [4]

FGHI

Step-by-step explanation:

The square FGHI needs to be created into a reflection for true congruence of the figure thus transformed across the axis.

FGHI's co-ordinates' signs are to be reversed for reflection thus coordinates:

2,-5

4,-5

2,-7

4,-7

are made into

-2,5

-4,5

-2,7

-4,7

5 0

2 years ago

Read 2 more answers

Expand using the properties and rules for logarithms

malfutka [58]

Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.$

2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.$

4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

Answer: correct option is B.

7 0

3 years ago