Answer:
Total resistance: 18 Ω
Total current: 0.5 A
VR1: 2.5 V
VR2: 1.5 V
VR3: 5 V
Explanation:
Two formulas/laws you <u><em>have </em></u>to know:
1) Resistors in series: Rtotal = R1 + R2 + ... (sum the individual resistors)
2) V=I·R a.k.a. I=V/R a.k.a. R=V/I (same formula in 3 shapes)
So, total resistance is sum off all three: 5+3+10 = 18Ω
Total current: I=V/R, V=9, R=18, so I = 9/18 = 0.5A
Voltage across resistor: V=I·R, I=0.5A (for all three), R=5 (for R1), so V = 0.5·5 = 2.5V. Same for the other three.
As a double check, the sum of the voltages must equal the battery voltage again, no volts ever get lost: 2.5+1.5+5 = 9V (check!!)
