The value of TC(10) is 5300 Dollars
Given function is TC(Q) = 500Q +300 dollars
We need to calculate the value for TC (10)
As we know that the equation given is TC(Q) = 500Q + 300 dollars
Q is the number of TVs produced
Therefore, The value of Q is 10 for TC(10)
Substituting the value of Q
in the total cost of flatiron TVs given by function TC(Q) = 500Q + 300 dollars That Q= 100,
TC(10) = 500(10)+300 dollars
∴ TC (10) = 5000+300 dollars
∴ TC (10) = 5300 dollars
Hence the value of TC(10) is 5300 Dollars
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The value of the collection originally was $1,000,000
What was the original value of the collection?
The original value of the collection is not known, hence, it is represented by X
The increase in value by $50,000 means that the value is X+$50,000
Now, when the error was discovered, it is now worth half of the value previously
The new value is (X+$50,000)*0.5
New value=(X+$50,000)*0.5
The new value at this point is $525,000
$525,000=(X+$50,000)*0.5
$525,000/0.5=X+$50,000
$1,050,000=X+$50,000
X=$1,050,000-$50,000
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<h3>
Answer: 8/25</h3>
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Explanation:
In a standard deck, there are 52 cards.
If this deck is missing the queen of hearts and 2 of clubs, then we really have 52-2 = 50 cards in the deck.
There are 4 aces and 13 spades. Those values add to 4+13 = 17, but we need to subtract off 1 to account for the ace of spades counted twice. We have 17-1 = 16 cards that are either an ace, a spade, or both.
Or you can think of it like saying 13 spades + 1 ace of hearts + 1 ace of diamonds + 1 ace of clubs = 16 cards total.
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The event space has A = 16 cards in it, while the sample space has B = 50 cards.
The probability we're after is A/B = 16/50 = 8/25
Answer:
Step-by-step explanation:
d=(10-3)^2+(8-8)^2=(7)^2+(0)^2=49
since it is in radical the the answer is 7
