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3 years ago

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Felix is printing orange and green forms. he notices that 9 orange forms fit on a page, and 10 green forms fit on a page. if Fel

ix wants to print the exact same number of orange and green forms, what is the minimum number of each form that he could print?

1 answer:

pochemuha3 years ago

8 0

The maximum number for each should 20! :)

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Order these numbers from least to greatest.<br> 3.195, 67/20, 3.19, 3 1/3

galina1969 [7]

The numbers from least to greatest are 3.19, 3.195, 3 1/3, and 67/20. This is because 67/20 is equivalent to 3.35 in decimal form, which is greater than all of the other numbers, including 3 1/3, which is 3.3333.

4 0

3 years ago

Which of the following is an infinite series?

max2010maxim [7]

Answer:

for the first question it would be A. 4+8+16+32 because infinite series are such as :

9,18,36,72,144,288

10,20,40,80,160,

so basically its multiplying *2

I cant do #2 without seeing the formula

4 0

3 years ago

Three friends each have some ribbon. Carol has 90 inches of ribbon, Tino has 7.5 feet of ribbon, and Baxter has 3.5 yards of rib

erastovalidia [21]

Answer: 306 inches or 25.5 feet or 8.5 yards.

Step-by-step explanation:

Given: Carol has 90 inches of ribbon, Tino has 7.5 feet of ribbon, and Baxter has 3.5 yards of ribbon.

1 feet = 12 inches

length of ribbon Tino has = 12 x 7.5 = 90 inches

1 yard = 36 inches

length of ribbon Baxter has = 3.5 x 36 = 126 inches

Total ribbon they have = (length of ribbon Carol has) + (length of ribbon Tino has) + (length of ribbon Baxter has)

= (90+90+126) inches

= 306 inches

In feet , Total ribbon = $\dfrac{306}{12}\text{ feet}$ $[\text{ 1 inch}=\dfrac{1}{12}\text{ feet}]$

$=\text{25.5 feet}$

In yards, Total ribbon = $\dfrac{25.5}{3}\text{ yards}$ $[\text{1 feet}=\dfrac{1}{3}\text{ yard}]$

$=\text{ 8.5 yards}$

Hence, the total length of ribbon the three friends have is 306 inches or 25.5 feet or 8.5 yards.

4 0

3 years ago

If possible help me in this. I need to find the two odd numbers...

Lelechka [254]

Part (a)

Consecutive odd integers are integers that odd and they follow one right after another. If x is odd, then x+2 is the next odd integer

For example, if x = 7, then x+2 = 9 is right after.

<h3>Answer: x+2</h3>

========================================================

Part (b)

The consecutive odd integers we're dealing with are x and x+2.

Their squares are x^2 and (x+2)^2, and these squares add to 394.

<h3>Answer: x^2 + (x+2)^2 = 394</h3>

========================================================

Part (c)

We'll solve the equation we just set up.

x^2 + (x+2)^2 = 394

x^2 + x^2 + 4x + 4 = 394

2x^2+4x+4-394 = 0

2x^2+4x-390 = 0

2(x^2 + 2x - 195) = 0

x^2 + 2x - 195 = 0

You could factor this, but the quadratic formula avoids trial and error.

Use a = 1, b = 2, c = -195 in the quadratic formula.

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(2)\pm\sqrt{(2)^2-4(1)(-195)}}{2(1)}\\\\x = \frac{-2\pm\sqrt{784}}{2}\\\\x = \frac{-2\pm28}{2}\\\\x = \frac{-2+28}{2} \ \text{ or } \ x = \frac{-2-28}{2}\\\\x = \frac{26}{2} \ \text{ or } \ x = \frac{-30}{2}\\\\x = 13 \ \text{ or } \ x = -15\\\\$

If x = 13, then x+2 = 13+2 = 15

Then note how x^2 + (x+2)^2 = 13^2 + 15^2 = 169 + 225 = 394

Or we could have x = -15 which leads to x+2 = -15+2 = -13

So, x^2 + (x+2)^2 = (-15)^2 + (-13)^2 = 225 + 169 = 394

We get the same thing either way.

<h3>Answer: Either 13, 15 or -15, -13</h3>

4 0

3 years ago

Evgesh-ka [11]

The Coefficient is 2.
The Constant is 4.
The Variable is x.

5 0

3 years ago