We have that
(3y-8)/12=(y/5)---------> 5*(3y-8)=12*(y)
15y-40=12y-------------> 15y-12y=40
3y=40--------------> y=40/3
y=(40/3)----------> 13.33
the answer is y=40/3 (13.33)
Answer:
111 apples cost $3.30 and 111 oranges cost $2 (1 apple costs nearly $0.03 and 1 orange costs nearly $0.02)
Step-by-step explanation:
Let the price of 111 apples be $x and the price of 111 oranges be $y.
1. 111 apples and 111 oranges cost $5.30, thus
x+y=5.30
2. 111 apples and 222 oranges cost $7.30, then
x+2y=7.30
Subtract the first equation from the second:
x+2y-x-y=7.30-5.30
y=2
Substitute it into the first equation:
x+2=5.30
x=3.30
111 apples cost $3.30 and 111 oranges cost $2 (1 apple costs nearly $0.03 and 1 orange costs nearly $0.02)
4x = 8 + 2x
4x - 2x = 8 + 2x -2x Subtract 2x from both sides
2x = 8 divide by 2
x = 4
1 in 12 chance of second person getting given a ticket
Then a 1 in 11 chance of the third person being given one.
1/12*1/11 = 1/132 chance. However, if it doesn't have to be in order, then there's a 1/12 chance of the third person getting a ticket, then a 1/11 chance of the second person getting one, so another 1/132 chance. Add them together for 2/132, or 1/66 chance