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2 years ago

What fraction is equivalent to 4 12?

Mathematics

2 answers:

nikdorinn [45]2 years ago

6 0

Is the fraction 4/12??

miskamm [114]2 years ago

6 0

Answer:

1/3

Step-by-step explanation:

1/3, 2/6, 3/9, 4/12.

are equivalent fractions. Equivalent fraction of a given fraction is got by multiplying or dividing its numerator and denominator by the same whole number.

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Given that x = 3, y = -2 and z = 0, calculate the value of each of the following algebraic expressions: 2x + y. Answer quick ple

icang [17]

2 times 3+(-2)
6-2
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3 years ago

The angle of depression from the basketball hoop to Claire’s eyes is 9.2°. The vertical distance from the ground to Claire’s eye

Marrrta [24]

we will isolate that right triangle marked off with the little angle thing.
We know that, in that right triangle, one of the legs measures 22 ft, and the angle (adjacent) to it, meausres 9.2 degreesIn this case, tan9.2=x/22 where x is that unkown length
cross multiply.
your final answer is equal to x+5.6

8 0

2 years ago

A tank contains 60 kg of salt and 1000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drain

MissTica

Answer:

(a) 60 kg; (b) 21.6 kg; (c) 0 kg/L

Step-by-step explanation:

(a) Initial amount of salt in tank

The tank initially contains 60 kg of salt.

(b) Amount of salt after 4.5 h

$\text{Let A = mass of salt after t min}\\\text{and }r_{i} = \text{rate of salt coming into tank}\\\text{and }r_{0} =\text{rate of salt going out of tank}$

(i) Set up an expression for the rate of change of salt concentration.

$\dfrac{\text{d}A}{\text{d}t} = r_{i} - r_{o}\\\\\text{The fresh water is entering with no salt, so}\\ r_{i} = 0\\r_{o} = \dfrac{\text{3 L}}{\text{1 min}} \times \dfrac {A\text{ kg}}{\text{1000 L}} =\dfrac{3A}{1000}\text{ kg/min}\\\\\dfrac{\text{d}A}{\text{d}t} = -0.003A \text{ kg/min}$

(ii) Integrate the expression

$\dfrac{\text{d}A}{\text{d}t} = -0.003A\\\\\dfrac{\text{d}A}{A} = -0.003\text{d}t\\\\\int \dfrac{\text{d}A}{A} = -\int 0.003\text{d}t\\\\\ln A = -0.003t + C$

(iii) Find the constant of integration

$\ln A = -0.003t + C\\\text{At t = 0, A = 60 kg/1000 L = 0.060 kg/L} \\\ln (0.060) = -0.003\times0 + C\\C = \ln(0.060)$

(iv) Solve for A as a function of time.

$\text{The integrated rate expression is}\\\ln A = -0.003t + \ln(0.060)\\\text{Solve for } A\\A = 0.060e^{-0.003t}$

(v) Calculate the amount of salt after 4.5 h

a. Convert hours to minutes

$\text{Time} = \text{4.5 h} \times \dfrac{\text{60 min}}{\text{1h}} = \text{270 min}$

b.Calculate the concentration

$A = 0.060e^{-0.003t} = 0.060e^{-0.003\times270} = 0.060e^{-0.81} = 0.060 \times 0.445 = \text{0.0267 kg/L}$

c. Calculate the volume

The tank has been filling at 6 L/min and draining at 3 L/min, so it is filling at a net rate of 3 L/min.

The volume added in 4.5 h is

$\text{Volume added} = \text{270 min} \times \dfrac{\text{3 L}}{\text{1 min}} = \text{810 L}$

Total volume in tank = 1000 L + 810 L = 1810 L

d. Calculate the mass of salt in the tank

$\text{Mass of salt in tank } = \text{1810 L} \times \dfrac{\text{0.0267 kg}}{\text{1 L}} = \textbf{21.6 kg}$

(c) Concentration at infinite time

$\text{As t $\longrightarrow \, -\infty,\, e^{-\infty} \longrightarrow \, 0$, so A $\longrightarrow \, 0$.}$

This makes sense, because the salt is continuously being flushed out by the fresh water coming in.

The graph below shows how the concentration of salt varies with time.

3 0

2 years ago

What is 25 squared? Please show work.

iragen [17]

25 squared is just 25 times 25 which equal 625

6 0

3 years ago

Read 2 more answers

I dunno this answer... pwease help... if you're smart

zmey [24]

Answer:

H: (2, 14)

O: (4,15)

U: (6,14)

S: (2,10)

E: (6,10)

Step-by-step explanation:

the image on the grid is after doin x- 1 and y-7

to get the preimage do the inverse , x + 1 , y + 7

note- a coordinate is written as (x,y)

so, add 1 to all the x's and 7 to all the y's on the coordinates on the grid!

and sorry for asking but, if this is right could i please get a thanks & brainliest recently a moderator deleted ALL my answers (over 400 answers) causing me to lose over 3k points so id appreciate it alot thanks xoxo

3 0

2 years ago