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Rina8888 [55]
3 years ago
7

Change the decimal 4.1 into a fraction

Mathematics
2 answers:
gayaneshka [121]3 years ago
6 0

Answer:

4  1/10

Step-by-step explanation:

You can take any number, such as 4.1, and write a 1 as the denominator to make it a fraction and keep the same value, like this:

4.1 / 1

To get rid of the decimal point in the numerator, we count the numbers after the decimal in 4.1, and multiply the numerator and denominator by 10 if it is 1 number, 100 if it is 2 numbers, 1000 if it is 3 numbers, and so on.

Therefore, in this case we multiply the numerator and denominator by 10 to get the following fraction:

41 / 10

Then, we need to divide the numerator and denominator by the greatest common divisor (GCD) to simplify the fraction.

The GCD of 41 and 10 is 1. When we divide the numerator and denominator by 1, we get the following:

41 / 10

Therefore, 4.1 as a fraction is as follows:

41 / 10

Bonus: If the answer above is an improper fraction, then we also display the mixed number answer below:

4  1/10

Iteru [2.4K]3 years ago
3 0

Answer: 41/10 is the fraction if you turn 4.1 into a decimal.

Step-by-step explanation:

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Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
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The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

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The present value of the loan is R576923.

<h3>What is compound interest ?</h3>

Compound interest is giving the current instalment in terms of the total previous amount.

The formula is given by

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In case the compound if interest is given every two months that is 6 instalments each year the above given formula will be

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According to the given question

Rate(r) = 7.5%

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4 days
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