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MAXImum [283]
3 years ago
11

What is the value of x in this triangle?

Mathematics
1 answer:
bekas [8.4K]3 years ago
5 0

Answer:

A is the answer

Step-by-step explanation:

3*30 is 90 2*30 is 60 and x*30 is 30 which means 90+60+30 equals 180

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3 years ago
3 more than x is less than 6
maria [59]

Answer:

x = 0

Step-by-step explanation:

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2 years ago
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at 111111:55\text{ p.m.}55 p.m.55, start text, space, p, point, m, point, end text, thomas ties a weight to the minute hand of a
Ahat [919]

The trigonometric function's formula, which simulates the torque (tau) that the weight applied t minutes after Thomas attached it is

3 Sin (\frac{2\frac{22}{7} }{60} (t-51))

The angular speed of the minutes hand is

w = \frac{2 (\frac{22}{7}) }{60} rad/min

Following the application of weight, the torque as a function of time t is,

t= t_{0} sin (w (t-5) min)\\ = (3 Nm) sin ((\frac{2 (\frac{22}{7} }{60} ) rad/min (t-5) min)

= (3 Nm) sin ( \frac{2 (\frac{22}{7} }{60} (t-5) rad ) \\= 3 sin (\frac{2 \frac{22}{7} }{60} (t-5)

<h3>What is torque ?</h3>

Torque, which is also known as the moment of a force, is the propensity of a force to rotate the body to which it is applied. Force (F) x Distance (r) = Torque is how torque is calculated. The distance (r) between the pivot point and the force's action point. A vector quantity is a torque. As a vector quantity, torque always has a direction that is perpendicular to the plane that contains the vectors of force and displacement.

To learn more about Torque, visit

brainly.com/question/16042080

#SPJ4

7 0
1 year ago
A group of friends wants to go to the amusement park. They have no more than $170 to spend on parking and admission. Parking is
babunello [35]

Answer:

$9 + 20p ≤ $145

Step-by-step explanation:

5 0
2 years ago
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Which portion of the unit circle satisfies the trigonometric inequality cos^2theta + sin^2theta is greater than or equal to 1. A
liberstina [14]

Answer:

Only points on the circle satisfy the given inequality.

Step-by-step explanation:

Given: Unit circle

To find: portion of the unit circle which satisfies the trigonometric inequality \sin ^2\theta +\cos ^2\theta \geq 1

Solution:

In the given figure, OA = 1 unit (as radius of the unit circle equal to 1)

\sin \theta = side opposite to \theta/hypotenuse

\cos  \theta = side adjacent to \theta/hypotenuse

\sin \theta =\frac{AB}{AO}\\\sin \theta =\frac{AB}{1}\\AB=\sin \theta

\cos  \theta=\frac{OB}{AO}\\\cos \theta =\frac{OB}{1}\\OB=\cos \theta

So, coordinates of A = \left ( \cos \theta ,\sin \theta  \right )

For any point (x,y) on the unit circle with centre at origin, equation of circle is given by x^2+y^2=1

Put (x,y)=\left ( \cos \theta ,\sin \theta  \right )

\cos ^2\theta +\sin ^2\theta =1

So, (x,y)=\left ( \cos \theta ,\sin \theta  \right ) satisfies the equation x^2+y^2=1

For points  (x,y)=\left ( \cos \theta ,\sin \theta  \right ) inside the circle, \cos ^2\theta +\sin ^2\theta

For points  (x,y)=\left ( \cos \theta ,\sin \theta  \right ) outside the circle, \cos ^2\theta +\sin ^2\theta >1

So, only points on the circle satisfy the given inequality.

4 0
2 years ago
Read 2 more answers
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