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kkurt [141]
3 years ago
12

Triangle ABC has vertices of A(-8,8),B(6,2),C(-2,1).Find the length of the median from C in triangle e abc

Mathematics
1 answer:
jekas [21]3 years ago
8 0
First find midpoint of AB and lastly find the length of midpoint and C

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Help! (3 3/4)÷(−2 1/2)=
UkoKoshka [18]

Step-by-step explanation:

33/4=8.25

-21/2= -10.5

8.25÷-10.5=0.785

5 0
3 years ago
For the graph of f (x) = | x |, what does the origin represent?
tino4ka555 [31]

Answer:

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8 0
3 years ago
Please help I really need your help
Amanda [17]

Answer:

1.  1200 \ kg/m^3

2.

a)

35 cm = 0.35 meters

11 dm = 1.1 meters

15 mm = 0.015 meters

b)

Volume = 0.005775 cubic meters

Mass = 15.5925 kilograms

Step-by-step explanation:

1.

We know

Density = Mass/Volume

Given

Mass = 90 kg

Volume = 0.075 cubic meters

The SI unit for density is kilograms per cubic meters. Our dimensions are just that, so we just need to plug in the numbers into the formula and get our answer. Shown below:

Density = \frac{90}{0.075}=1200 \ kg/m^3

The Density of asphalt block = 1200 \ kg/m^3

2.

a)

We need to express 35cm, 11dm, and 15mm in meters

We know

100 cm = 1 meters, so

35 cm = 35/100 = 0.35 meters

We know 1 dm = 0.1 meters, so

11 dm * 0.1 = 1.1 meters

We know, 1mm = 0.001 meters, so

15 mm * 0.001 = 0.015 meters

b)

Volume of the Slab is length * width * height, in meters, that would be:

Volume = 0.35 * 1.1 * 0.015 = 0.005775 cubic meters

THe mass would be found by the formula:

Density = Mass/Volume

2700 = Mass/0.005775

Mass = 0.005775 * 2700 =  15.5925 kilograms

5 0
3 years ago
Find the missing coordinate to complete the ordered pair.
MA_775_DIABLO [31]
(9,-4) you have to plugin 9 to the equation in the form of x. Then you add 5 and that would be your y value
8 0
3 years ago
Samples of a cast aluminum part are classified on the basis of surface finish (in microinches) and edge finish. The results of 1
liubo4ka [24]

Answer:

a) P (A)= 88/102= 0.8627

(b) P (B)=  89/102= 0.8725

c) P (A`) =  14/102 = 0.1372

(d) P (A∩B) = 84/102 =0.8235

(e) P(AUB)= 93/102 = 0.9117

(f)P (A`UB) = 98/102= 0.96078

Step-by-step explanation:

                                                                   edge                  

                                                  finish excellent       good           Total

<u>(A )surface finish excellent            84                      4                  88</u>

good                                    ( B) ⇵    5                       9                  14

Total                                               89                      13                102

a) Upper P left-parenthesis Upper A right-parenthesis equals

P (A)= 88/102= 0.8627

All the elements of set A = 84+4= 88

(b) Upper P left-parenthesis Upper B right-parenthesis equals

P (B)=  89/102= 0.8725

All the elements of set B = 84+5= 89

c) Upper P left-parenthesis Upper A prime right-parenthesis equal

P (A`) =  14/102 = 0.1372

All the elements of Universal set U which are not elements of set A = 102- 88= 14

(d) Upper P left-parenthesis Upper A intersection Upper B right-parenthesis equals

P (A∩B) = 84/102 =0.8235

Only those elements of set A and set B which are common

(e) Upper P left-parenthesis Upper A union Upper B right-parenthesis equals

P(AUB)= 93/102 = 0.9117

Totalling elements of set A and B= 88+5= 93

(f) Upper P left-parenthesis Upper A prime union Upper B right-parenthesis equals

P (A`UB) = 98/102= 0.96078

All the elements of Universal set U which are not elements of set A and the elements of Set B = 5+9+ 84= 98

6 0
3 years ago
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