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zaharov [31]
3 years ago
11

Y= - x+2 Y=3x-4 Estimate the solution to the system of equations

Mathematics
1 answer:
IrinaVladis [17]3 years ago
8 0

Answer:

x=\frac{3}{2}\\ y=\frac{1}{2}

Step-by-step explanation:

y=-x+2\\y=3x-4

Let's solve one of them for x.

y=3x-4

Add 4

y+4=3x

Divide by 3.

x=\frac{y+4}{3}

Now, plug the value of y in the formula, or you can plug the value of x in the other equation. I'll take this one.

x=\frac{y+4}{3}

x=\frac{(-x+2)+4}{3}

x=\frac{-x+2+4}{3}

x=\frac{-x+6}{3}

Multiply by 3 to get rid of the denominator.

3x=-x+6

add x

3x+x=6

Combine like terms;

4x=6

Divide by 4.

x=\frac{6}{4}

Simplify.

x=\frac{3}{2}

Now that you found the value of x, replace it in any of the equations to find y.

y=-x+2\\y=-(\frac{3}{2})+2\\ y=-\frac{3}{2}+2

y=\frac{-3+2*2}{2} \\y=\frac{-3+4}{2} \\y=\frac{1}{2}

Proof:

y=3x-4\\\frac{1}{2}=3(\frac{3}{2})-4\\\frac{1}{2}=(\frac{9}{2})-4

\frac{1}{2}=\frac{9-4*2}{2}

\frac{1}{2}=\frac{9-8}{2}

\frac{1}{2}=\frac{1}{2}

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For a year, a chef from a restaurant collected data about the cost of strawberries and cherries in his local food market. this d
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A Strawberries generally cost less.

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Step-by-step explanation:

A and D

5 0
3 years ago
You are enclosing a rectangular garden with 180 feet of omamental fencing. The area of the garden is 1800 square feet. What are
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Step-by-step explanation:

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P = 2L + 2W.  We are given the perimeter as 180 feet, so

180 = 2L + 2W.  Solve this for either L or W.  I chose W, no reason...

180 - 2L = 2W so

90 - L = W  Hold that thought.  We'll come back to it in a minute.

Area is

A = LW.  We are given the area as 1800 square feet, so

1800 = LW.  Sub in 90 - L for W:

1800 = L(90 - L).  Distribute to get a quadratic:

1800=90L-L^2

Get everything on one side and solve for the length by factoring:

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Factor this however you like to factor quadratics, to get the length of

L = 30 and L = 60.  First off, the length is longer than the width in general, so if we want to solve for the width, plug in 60 as L in the equation in bold print:

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4 0
3 years ago
A fair coin is to be tossed 20 times. Find the probability that 10 of the tosses will fall heads and 10 will fall tails, (a) usi
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Using the distributions, it is found that there is a:

a) 0.1762 = 17.62% probability that 10 of the tosses will fall heads and 10 will fall tails.

b) 0% probability that 10 of the tosses will fall heads and 10 will fall tails.

c) 0.1742 = 17.42% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item a:

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 20 tosses, hence n = 20.
  • Fair coin, hence p = 0.5.

The probability is <u>P(X = 10)</u>, thus:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{20,10}.(0.5)^{10}.(0.5)^{10} = 0.1762

0.1762 = 17.62% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item b:

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • The binomial distribution is the probability of <u>x successes on n trials, with p probability</u> of a success on each trial. It can be approximated to the normal distribution with \mu = np, \sigma = \sqrt{np(1-p)}.

The probability of an exact value is 0, hence 0% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item c:

For the approximation, the mean and the standard deviation are:

\mu = np = 20(0.5) = 10

\sigma = \sqrt{np(1 - p)} = \sqrt{20(0.5)(0.5)} = \sqrt{5}

Using continuity correction, this probability is P(10 - 0.5 \leq X \leq 10 + 0.5) = P(9.5 \leq X \leq 10.5), which is the <u>p-value of Z when X = 10.5 subtracted by the p-value of Z when X = 9.5.</u>

X = 10.5:

Z = \frac{X - \mu}{\sigma}

Z = \frac{10.5 - 10}{\sqrt{5}}

Z = 0.22

Z = 0.22 has a p-value of 0.5871.

X = 9.5:

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.5 - 10}{\sqrt{5}}

Z = -0.22

Z = -0.22 has a p-value of 0.4129.

0.5871 - 0.4129 = 0.1742.

0.1742 = 17.42% probability that 10 of the tosses will fall heads and 10 will fall tails.

A similar problem is given at brainly.com/question/24261244

6 0
3 years ago
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