Using the equation x – 3y = -21, create a system of equations that can be easily solved using the addition
1 answer:
You might be interested in
The sequence of transformations used to obtain figure A'B'C'D'from figure ABCD are a reflection across the y-axis followed by a horizontal translation 1 unit right
<h3>Complete question</h3>Figure ABCD is transformed to figure A'B'C'D', as shown below: (see attachment)
Which of the following sequences of transformations is used to obtain figure A'B'C'D'from figure ABCD?
<h3>How to determine the transformation?</h3>From the attached figure, we can see that:
ABCD and A'B'C'D' are on either sides of the y-axis.
This means that ABCD is first reflected across the y-axis.
ABCD is 2 units from the y-axis, while A'B'C'D' is 1 unit from the y-axis.
This means that the reflection is followed by a translation.
The unit of translation is:
Unit = 2 - 1
Evaluate
Unit = 1
1 represents a right translation
Hence, the sequence of transformations are a reflection across the y-axis followed by a horizontal translation 1 unit right
Read more about transformation at:
#SPJ1
Answer:
The bacteria population will change with a growth factor of 1/12 for every half an hour or 1/12 per 30 minutes. (I don't know what the options are, but anything related to the answer I gave should be right.)
Step-by-step explanation:
Simple mathematics should get you the right answer. Here we are dealing with a fraction in a fraction. The first scenario should look like this: <u>1/6 / 1</u>. Basically, that looks like one-sixth over one. Obviously, if we divide 1/6 by 1, we would get 1/6 itself again and we want to know what growth factor the population changes by for every half an hour. There are <u>30 minutes</u> in half an hour and <u>60 minutes</u> in one hour. Let's use the simplified terms to our advantage. Now, our first scenario should look like this: <u>1/6 / 60</u>. Looks better now doesn't it? (Check the linked image to see the full scenario and how I did it in this next part.) For me, I divided 60 by 30 to get the scale factor, which is 2, then I divide 2 by 1/6 to get 1/12. Finally, we have 1/12 per half an hour! If I am wrong, please let me know and I hope this helps! :D
Given a quadratic equation in standard form
The discriminant D
tells the types of roots the equation has.
In this case, we have
Then, the discriminant of this quadratic equation will be
Finally, the value of discriminat is 49 and as he discriminant is greater than zero then this quadratic equation has 2 different real solutions.