The minimum value for g(x)=x² - 10x + 16 is -9
<h3>How to determine the minimum value?</h3>
The function is given as:
g(x)=x² - 10x + 16
Differentiate the function
g'(x) = 2x - 10
Set the function 0
2x - 10 = 0
Add 10 to both sides
2x = 10
Divide by 2
x = 5
Substitute 5 for x in g(x)
g(5)=5² - 10*5 + 16
Evaluate
g(5) = -9
Hence, the minimum value for g(x)=x² - 10x + 16 is -9
Read more about quadratic functions at:
brainly.com/question/7784687
Yeah, base is ten and the two sides are 5...
Answer:
-21
Step-by-step explanation:
because theres two negitives so it makes it a positive
Answer:
B. (x-3)^2
Step-by-step explanation:
x^2-6x+9 = (x-3)^2
(a-b)^2=a^2-2ab+b^2
(a+b)^2=a^2+2ab+b ^2
