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Nikolay [14]
3 years ago
15

This Venn diagram has three regions.

Mathematics
1 answer:
Kobotan [32]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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Help me out plz I need an answer
weeeeeb [17]
The correct answer is B
Hope this helped :)
7 0
3 years ago
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1. What is the radius<br> (1 Point)<br> 11 cm
mr_godi [17]

Given that we need to determine the radius of the circle.

<u>Radius:</u>

By definition of radius of circle, the radius is the  length of the line which is drawn from the center of the circle to any point on the circle.

From the figure, we need to determine the radius of the circle.

As, we can see that, the distance from the center of the circle to the point on the circle is 11 cm.

Since, we know that, the radius is the distance from the center of the circle to the point on the circle then, the radius of the given circle is 11 cm

Thus, radius of the circle is 11 cm.

3 0
3 years ago
Find the point P on the line y=2x that is closest to the point (20,0) .what is the least distance between pans (20,0)?
Vsevolod [243]
The closest point on a line, to another point, will be a point that's on a normal of that line, or a line that is perpendicular to it, notice picture below

so, y = 2x, has a slope of 2, a perpendicular line to it, will have a slope of negative reciprocal that, or \bf 2\qquad negative\implies -2\qquad reciprocal\implies \cfrac{1}{-2}\implies -\cfrac{1}{2}

so, we know that line passes through the point 20,0, and has a slope of -1/2

if we plug that in the point-slope form, we get \bf y-0=-\cfrac{1}{2}(x-20)\implies y=-\cfrac{1}{2}x+10

now, the point that's on 2x and is also on that perpendicular line, is the closest to 20,0 from 2x, thus, is where both graphs intersect, as you can see in the graph

thus  \bf 2x=-\cfrac{1}{2}x+10  solve for "x'

------------------------------------------------------------

not sure on the 2nd part, but sounds like, what's the distance from that point to 20,0, well, if that's the case, just use the distance equation

\bf \textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ \square }}\quad ,&{{ \square }})\quad &#10;%  (c,d)&#10;&({{ \square }}\quad ,&{{ \square }})&#10;\end{array}\qquad &#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}


6 0
3 years ago
Circle A has center of (4, 6) and a radius of 5, and circle B has a center of (1, 0) and a radius of 15.What steps will help sho
melisa1 [442]

Answer:

Dilate circle A by a scale factor of 3.

Step-by-step explanation:

Generally, similar figures have sides in the same ratio

3(5) = 15

When dilate A by factor 3, it will look exactly like B

4 0
3 years ago
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How I need to do.Gary has 58 trading cards on monday .on tuestay.his friend,Harry gave him some more.After that .Gary had 82 tra
rewona [7]
You have to make it into a subtraction problem. 82-58=24

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3 years ago
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