Area =

Area = 22/7 x 10 x 10
Area = 314 in^2
(the answer is option A, its rounded)
Hope this helps
Answer:
2³² -1
Step-by-step explanation:
The sequence has a₁ = 1 and r = 2. Filling in the numbers for n=32, we have ...
S₃₂ = 1·(1 -2³²)/(1 -2)
S₃₂ = 2³² -1
Answer:
252 Inches cube
Step-by-step explanation:
<em>So for this question you need to find the area of cross section which is the H,</em>
2 Times (3 Inches by 7 Inches) {The 2 same shape}
+
3 Inches by 7 Inches {The middle shape}
<u>For </u><u>the </u><u>H </u><u>Shape </u><u>=</u><u> </u><u>6</u><u>3</u><u> </u><u>Inches </u><u>Square</u>
<em>Then you'll time the lenght which is given 4 Inches</em>
63 Inches square ×4 Inches
252 Inches Cube
<u>The </u><u>volume </u><u>of </u><u>this </u><u>shape </u><u>will </u><u>be </u><u>2</u><u>5</u><u>2</u><u> </u><u>Inches </u><u>cube</u>
<u>Hope </u><u>this </u><u>helps </u><u>d</u><u>ont </u><u>hesitate</u><u> to</u><u> </u><u>ask </u><u>any </u><u>question!</u><u>!</u>
<u>Mark </u><u>me </u><u>as </u><u>brainliest</u><u> </u><u>aslo </u><u>appreciated!</u><u>!</u><u> </u><u>Tq</u>
Speed=distance/time
suppose the distance of the first day is d, and the time is t
distance of the second day: d+0.17d=1.17d
time of the second day: t+0.2t=1.2t
speed of the second day: 1.17d/1.2t=0.975(d/t)=(1-0.025)(d/t)
so the speed of the second day is 2.5% slower than the first day.
Answer:
Four significant figures
Step-by-step explanation:
Rules of significant figure:
1. Zeros before any non-zero digit are considered to be NON-significant.
2. Any zeros between any non-zero digits are SIGNIFICANT
0.505
Here, there are three significant digits: 505
3. Any zeros that are to the right of the decimal point and a non-zero number are SIGNIFICANT.
4.0000
4. All non - zero digit are significant
Therefore,
0.002040 has four significant figures
2040