Find the perimeter of each figure. Simplify.

Mathematics

1 answer:

Kay [80]4 years ago

3 0

Answer:

5)14x+4

6)20x

Step-by-step explanation:

5)8x+6x+4

6) 5x×4

You might be interested in

What number lies between 7x8/10=

zzz [600]

The number that lies between that is 7

3 0

3 years ago

Read 2 more answers

X^-9*x^-2 a 1/x^18 b 1/x^11 c x^18 d x^11

d1i1m1o1n [39]

Exponent rule : a^-x = 1/a^x

x^-9 * x^-2 =
1/x^9 * 1/x^2 = (when multiplying exponents with same base, add exponents)
1/x^(9 + 2) =
1/x^11

4 0

3 years ago

(points on a circle) PLEASE HELP THIS IS DUE TONIGHT

VashaNatasha [74]

Answer:

Inside the circle, a distance of $\sqrt{34}$ from the center of the circle.

Step-by-step explanation:

Center of circle is at (0,0)

One point of the circle is at (0, $\sqrt{38}$ )

Since the only known point is in the y-axis, the radius of the circle must be $\sqrt{38}$ .

$\sqrt{38}$ = 6.164

So the point (-5,-3) is still inside the circle as the distance from point (-5,-3) to the center of the circle is $\sqrt{(5)^2+(-3)^2}$ or $\sqrt{34}$ which is less than the radius of the circle.

7 0

3 years ago

Is it true that the integral LaTeX: \int x^2e^{2x}dx ∫ x 2 e 2 x d x can be evaluated using integration by parts? If so, state t

Marysya12 [62]

Answer:

Yes the integral can be evaluated by integration by parts as solved below.

Step-by-step explanation:

$\int x^{2}e^{2x}dx$

Taking algebraic function as first function and exponential function as second function we have

$\int x^{2}e^{2x}dx=x^{2}\int e^{2x}dx-\int (x^{2})'\int e^{2x}dx\\\\=x^{2}\frac{e^{2x}}{2}-\int 2x\times \frac{e^{2x}}{2}dx\\\\\frac{x^{2}e^{2x}}{2}-\int xe^{2x}dx\\\\Now\\\\\int xe^{2x}dx=x\int e^{2x}dx-\int 1\cdot \int e^{2x}dx\\\\=\frac{xe^{2x}}{2}-\int \frac{e^{2x}}{2}dx\\\\\frac{xe^{2x}}{2}-\frac{e^{2x}}{4}\\\\\therefore \int x^{2}e^{2x}dx=\frac{x^{2}e^{2x}}{2}-\frac{xe^{2x}}{2}+\frac{e^{2x}}{4}$