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dimulka [17.4K]
2 years ago
8

PLEASE HELP WILL MARK BRAINLIST AND GIVE 20 POINTS

Mathematics
2 answers:
TiliK225 [7]2 years ago
8 0

Answer:

The first one

Step-by-step explanation:

You just need to find the slope in the average of all the dots.

Gnoma [55]2 years ago
3 0

Answer:

the first option, y=3/7x-3

Step-by-step explanation:

the scatterplot begins around y=-3, so therefore the y-intercept is -3. The slope is obviously not higher than 1, so it is y=3/7x-3.

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Write 3.29 as a fraction or a mixed number
gregori [183]
3.29=3\frac{29}{100}=\frac{329}{100}
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3 years ago
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Find the value of 3 square root of 1000​
irga5000 [103]
The answer to this is 10
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Suppose you toss a fair coin 10 times, let X denote the number of heads. (a) What is the probability that X=5? (b) What is the p
zubka84 [21]

Answer:  The required answers are

(a) 0.25,    (b) 0.62,    (c) 6.

Step-by-step explanation:  Given that we toss a fair coin 10 times and X denote the number of heads.

We are to find

(a) the probability that X=5

(b) the probability that X greater or equal than 5

(c) the minimum value of a such that P(X ≤ a) > 0.8.

We know that the probability of getting r heads out of n tosses in a toss of coin is given by the formula of binomial distribution as follows :

P(X=r)=^nC_r\left(\dfrac{1}{2}\right)^r\left(\dfrac{1}{2}\right)^{n-r}.

(a) The probability of getting 5 heads is given by

P(X=5)\\\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}\\\\\\=\dfrac{10!}{5!(10-5)!}\dfrac{1}{2^{10}}\\\\\\=0.24609\\\\\sim0.25.

(b) The probability of getting 5 or more than 5 heads is

P(X\geq 5)\\\\=P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}+^{10}C_6\left(\dfrac{1}{2}\right)^6\left(\dfrac{1}{2}\right)^{10-6}+^{10}C_7\left(\dfrac{1}{2}\right)^7\left(\dfrac{1}{2}\right)^{10-7}+^{10}C_8\left(\dfrac{1}{2}\right)^8\left(\dfrac{1}{2}\right)^{10-8}+^{10}C_9\left(\dfrac{1}{2}\right)^9\left(\dfrac{1}{2}\right)^{10-9}+^{10}C_{10}\left(\dfrac{1}{2}\right)^{10}\left(\dfrac{1}{2}\right)^{10-10}\\\\\\=0.24609+0.20507+0.11718+0.04394+0.0097+0.00097\\\\=0.62295\\\\\sim 0.62.

(c) Proceeding as in parts (a) and (b), we see that

if a = 10, then

P(X\leq 0)=0.00097,\\\\P(X\leq 1)=0.01067,\\\\P(X\leq 2)=0.05461,\\\\P(X\leq 3)=0.17179,\\\\P(X\leq 4)=0.37686,\\\\P(X\leq 5)=0.62295,\\\\P(X\leq 6)=0.82802.

Therefore, the minimum value of a is 6.

Hence, all the questions are answered.

3 0
3 years ago
I will give BRAINLIEST! help open the picture!​
geniusboy [140]

Answer:

5/2

Step-by-step explanation:

8 0
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Plz help with this math question.Thx:) Don't forget to show your work.
sergij07 [2.7K]
You can use any data set in this table (except the row with x) to get the ratio.

so 20/196 is the ratio which equals about .102041

then multiply that decimal by the weight in the x row to see what x is

so 1078(.102041) = 110.000198 just round that to 110. you can also verify that ratio by checking other data points. for instance

490(.102041) = 50.00009 or 50

so you know x is 50 so answer is either b or d

then you know the ratio .102041, so does (10/98) = .102041

or does (98/10) = .102041

if you do the division you will see that (10/98) = .102041

so the answer is D
5 0
3 years ago
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