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mr Goodwill [35]
3 years ago
9

9.29 in fraction form

Mathematics
2 answers:
Volgvan3 years ago
5 0
929⁄<span>100 is the exact answer</span>
Darina [25.2K]3 years ago
5 0
9 29
100is the fraction form of the decimal 9.29
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Line AB passes through points A(–6, 6) and B(12, 3). If the equation of the line is written in slope-intercept form, y = mx + b,
inn [45]

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points A(-6, 6) and B(12, 3). Substitute:

m=\dfrac{3-6}{12-(-6)}=\dfrac{-3}{18}=-\dfrac{3:3}{18:3}=-\dfrac{1}{6}

Therefore we have y=-\dfrac{1}{6}x+b.

Put the coordinates of the point B to the equation:

3=-\dfrac{1}{6}(12)+b

3=-2+b          <em>add 2 to both sides</em>

5=b\to b=5

Answer:

m=-\dfrac{1}{6}\\\\b=5

8 0
3 years ago
Explain why we can use any two points on a line to find the slope of the line
ololo11 [35]

Because all the coordinates of a line has the same slope. So, we can use any two of them to find the slope.


6 0
3 years ago
Read 2 more answers
Let log_(b)A=3; log_(b)C=2; log_(b)D=5 what is the value of log_(b)((A^(5)C^(2))/(D^(6)))
Colt1911 [192]

Answer:

-11

Step-by-step explanation:

Given

\log_bA=3\\ \\\log_bC=2\\ \\\log_bD=5

Use properties:

\log_b(A\cdot C)=\log_bA+\log_bC\\ \\\log_b\dfrac{A}{C}=\log_bA-\log_bC\\ \\\log_bA^k=k\log_bA

Thus,

\log_b\dfrac{A^5\cdot C^2}{D^6}\\ \\=\log_b(A^5\cdot C^2)-\log_bD^6\\ \\=\log_bA^5+\log_bC^2-\log_bD^6\\ \\=5\log_bA+2\log_bC-6\log_bD\\ \\=5\cdot 3+2\cdot 2-6\cdot 5\\ \\=15+4-30\\ \\=-11

3 0
3 years ago
If a ray lays in a plane, how many points of the ray are also in the plane?
Over [174]
The answer is a all of the points
6 0
3 years ago
Read 2 more answers
use the formulas for lowering powers to rewrite the expression in terms of the first power of cosine cos^4
Firdavs [7]

The expression cos⁴ θ in terms of the first power of cosine is <u>[ 3 + 2cos 2θ + cos 4θ]/8.</u>

The power-reducing formula, for cosine, is,

cos² θ = (1/2)[1 + cos 2θ].

In the question, we are asked to use the formulas for lowering powers to rewrite the expression in terms of the first power of cosine cos⁴ θ.

We can do it as follows:

cos⁴ θ

= (cos² θ)²

= {(1/2)[1 + cos 2θ]}²

= (1/4)[1 + cos 2θ]²

= (1/4)(1 + 2cos 2θ + cos² 2θ] {Using (a + b)² = a² + 2ab + b²}

= 1/4 + (1/2)cos 2θ + (1/4)(cos ² 2θ)

= 1/4 + (1/2)cos 2θ + (1/4)(1/2)[1 + cos 4θ]

= 1/4 + cos 2θ/4 + 1/8 + cos 4θ/8

= 3/8 + cos 2θ/4 + cos 4θ/8

= [ 3 + 2cos 2θ + cos 4θ]/8.

Thus, the expression cos⁴ θ in terms of the first power of cosine is <u>[ 3 + 2cos 2θ + cos 4θ]/8</u>.

Learn more about reducing trigonometric powers at

brainly.com/question/15202536

#SPJ4

5 0
2 years ago
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