Answer:
Therefore the mass of the of the oil is 409.59 kg.
Step-by-step explanation:
Let us consider a circular disk. The inner radius of the disk be r and the outer diameter of the disk be (r+Δr).
The area of the disk
=The area of the outer circle - The area of the inner circle
= 
![=\pi [r^2+2r\triangle r+(\triangle r)^2-r^2]](https://tex.z-dn.net/?f=%3D%5Cpi%20%5Br%5E2%2B2r%5Ctriangle%20r%2B%28%5Ctriangle%20r%29%5E2-r%5E2%5D)
![=\pi [2r\triangle r+(\triangle r)^2]](https://tex.z-dn.net/?f=%3D%5Cpi%20%5B2r%5Ctriangle%20r%2B%28%5Ctriangle%20r%29%5E2%5D)
Since (Δr)² is very small, So it is ignorable.
∴
The density 
We know,
Mass= Area× density
Total mass 
Therefore
![=40\pi[ln(1+r^2)]_0^5](https://tex.z-dn.net/?f=%3D40%5Cpi%5Bln%281%2Br%5E2%29%5D_0%5E5)
![=40\pi [ln(1+5^2)-ln(1+0^2)]](https://tex.z-dn.net/?f=%3D40%5Cpi%20%5Bln%281%2B5%5E2%29-ln%281%2B0%5E2%29%5D)
= 409.59 kg (approx)
Therefore the mass of the of the oil is 409.59 kg.
I cant really see that- could you tell me what that is?
<span>This is an isosceles triangle. If each side is 1, we can find the hypotenuse using the Pythagorean theorem.
a^2 + b^2 = c^2
1^2 + 1^2 = c^2
1 + 1 = c^2
2 = c^2
root 2 = c
Thus, the answer is root 2.
Hope this helps :)</span>
Answer:
- leading coefficient: 2
- degree: 7
Step-by-step explanation:
The degree of a term with one variable is the exponent of the variable. The degrees of the terms (in the same order) are ...
6, 0, 7, 1
The highest-degree term is 2x^7. Its coefficient is the "leading" coefficient, because it appears first when the polynomial terms are written in decreasing order of their degree:
2x^7 -7x^6 -18x -4
The leading coefficient is 2; the degree is 7.
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<em>Additional comment</em>
When a term has more than one variable, its degree is the sum of the exponents of the variables. The term xy, for example, is degree 2.
