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tatuchka [14]
3 years ago
15

Tutor O-Rama claims that their services will raise student SAT math scores at least 50 points. The average score on the math por

tion of the SAT is μ=350 and σ=35. The 100 students who completed the tutoring program had an average score of 385 points. Is the students’ average score of 385 points significant at the 5% and 1% levels to support Tutor O-Rama’s claim of at least a 50-point increase in the SAT score? (2 pts) Is the Tutor O-Rama students’ average score of 385 points significantly different at the 5% and 1% levels from the average score of 350 points on the math portion of the SAT? What conclusion can you make, based on your results, about the effectiveness of Tutor O-Rama’s tutoring? (2 pts)
Mathematics
1 answer:
Novosadov [1.4K]3 years ago
4 0

Answer:

See below

Step-by-step explanation:

The score increase was 35 points. They claimed an increase of at least 50 points.  For a significance level of 5%, the z-score for the situation needs to be at smaller than -1.645.  For a significance level of 1%, the z-score needs to be smaller than -2.325

The z score for our situation:  z = (385 - 350)/50 = 0.7

The average score of 385 of Tutor O-Rama scores is not significantly different from the average of the other students SAT scores.  The evidence doesn't support their claim of being effective tutoring.

 

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Answer:

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Step-by-step explanation:

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Entering GPA   0.090953          0.022162        4.103932       0.003419

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\hat \beta = 0.090953\\SE (\hat \beta)=0.022162

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t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306

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CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)

Thus, the 95% confidence interval for the true slope is (0.03985, 0.14206).

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