in this reflection, the image has been reflected along the x = 3 line. then all the points on the image are reflected along this vertical line. the distance between each point and the vertical line is noted and by that same distance its moved to the opposite side of the vertical line, while the y coordinates stay the same.

A(2,-5)- x coordinate is 2, its 1 unit away from x=3, it should move by 1 unit to the other side of x = 3, then x = 4. y stays as it is.

A' - (4,-5)

B(-4,6) - distance from x = 3, is (-4-+3) is seven units, moves by 7 units to the other side

B' (10,6)

C(3,1) = distance from 3 = 0, therefore the point stays at is,

C' (3,1)

Q2)

next is a translation, in translation the size nor shape changes, each point in the original image moves the same distance in the same direction.

T (3,-6) (x,y) = this means that the x coordinates move by +3 points to the right and y coordinates move downwards by 6 units

A (2,-5) ---> (2+3,-5-6)

A' (5,-11)

B (-4,6) ---> (-4+3,6-6)

B' (-1,0)

C (3,1) ---> (3 + 3, 1-6)

C' (6,-5)

Q3)

r(90°,0)

this is a rotation done in the clockwise direction. then the image takes a rotation to the right direction around the origin.

then the x, y coordinates of the preimage become ;

(x,y) = (y,-x)

A(2,-5) --> A' = (-5,-2)

B(-4,6) ---> B' = (6,4)

C(3,1) ---> C' = (1,-3)

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3 years ago

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PLS HELP I DONT UNDERSTAND!! What type of circle would you use when graphing x≥5

inna [77]

How to:

When graphing a linear inequality on a number line, use an open circle for "less than" or "greater than", and a closed circle for "less than or equal to" or "greater than or equal to".

For this problem:

For the number line, we would place a solid dot at −5 because the value is both greater than and equal too (≥) and then continue a line on the number line to the right of that point incorporating all values greater than −5

Answer:

(image attached) 

Look at the one showing your problem, the first one.

It's reverse of that since X is greater meaning the line goes the other way instead as shown in the second image.

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