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schepotkina [342]
3 years ago
6

Luke ate a snack with 91 total calories. If the chips he ate were 41.2 calories, how many calories were in the rest of his snack

?
Mathematics
1 answer:
Sholpan [36]3 years ago
5 0

Answer:

49.8

Step-by-step explanation:

91-41.2

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hammer [34]
So you would multiply if it has the word of in the problem right?

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3 years ago
Verizon has a special and is selling the new iPhone 7 for $299 to new customers. If the Apple Store is charging twice as much as
-Dominant- [34]

Answer:

$598

Step-by-step explanation:

2 x 299 = 598 so Apple is charging $598 for the new phone.

6 0
2 years ago
Factor 2a2b3 - 14ab + 16a
zhuklara [117]

Answer:

2a(b^3 - 7b + 8)

Step-by-step explanation:

I'm assuming that 2a2b3 is 2a2b^2. If not, this answer isn't correct.

Look at the whole numbers. Is there a number that divides into them evenly? Yes, 2, so you pull 2 from the problem and divide each number by 2. Do the same for each variable.

2a2b3 - 14ab + 16a

2(ab^3 - 7ab +8a)

2a(b^3 - 7b + 8)

6 0
3 years ago
Write a compound interest function to model each situation. Then find the balance after the given number of years.
andriy [413]

Answer:

See explanation

Step-by-step explanation:

The standard compound interest formula is A = P(1+\frac{r}{n})^{nt} where:

P is the principal amount

r is the interest rate (typically as a percentage)

t is the time

n is the times compounded per unit of time

So,

1)  A = 50000(1+\frac{0.03}{12})^{(12)(6)} =59847.42

2) A = 43000(1+\frac{0.05}{1})^{(1)(3)} =49777.88

3) A = 65000(1+\frac{0.06}{4})^{(4)(12)} =132826.08

You should check my answers though, I may have mixed up some terms.

3 0
3 years ago
WILL GIVE BRAINLIEST
stira [4]

The air force plane travelled for a total of 6.9 hours.

<u>SOLUTION: </u>

Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph.  A cargo plane left sometime later flying in the same direction at an average speed of 207 mph.  After flying for 5.3 hours the cargo plane caught up with the Air Force plane.  

We have to find the number of hours the Air Force plane flew before the cargo plane caught up.

Now, we know that, \text { distance travelled }=\text { speed } \times \text { time }

For air force plane \rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }

\text { For cargo plane } \rightarrow \text { distance travelled }=207 \times 5.3 \text { hours }

Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.

So, 159 \times \text { time taken by air force plane }=207 \times 5.3

\Rightarrow =\frac{207 \times 5.3}{159}

\Rightarrow =\frac{1097.1}{159}

Time taken by air force plane = 6.9  hrs

6 0
3 years ago
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