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schepotkina [342]
3 years ago
6

Luke ate a snack with 91 total calories. If the chips he ate were 41.2 calories, how many calories were in the rest of his snack

?
Mathematics
1 answer:
Sholpan [36]3 years ago
5 0

Answer:

49.8

Step-by-step explanation:

91-41.2

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Linda paid $48 for a jacket that was on sale for 25% of the original price. What was the original price of the jacket
kap26 [50]
$48/x 25%/100
 
48 x 100= 4800
4800 / 25= 192
 answer: $192

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Match each step with the correct expression to factor s2 + 78 + 6 by using the decomposition method.​
Vinvika [58]

Answer:

did u got the answer?

Step-by-step explanation:

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Multiply.
Vedmedyk [2.9K]

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Hello, There! i Noticed that your Question is 4.62 x 106 I'm Suggesting you mean 4.2 x 10 to the 6th power.

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2 years ago
Which equation represents a line that passes through (-2, 4) and has a slope of 2/5
Ronch [10]

An equation represents a line that passes through (-2, 4) and has a slope of 2/5 is y-4 = 2/5(x+2)

<h3>Equation of a line</h3>

The equation of a line in point-slope form is expressed as;

y-y1 = m(x - x1)

where

m is the slope

(x1, y1) is any pint on the line

Substitute the given parameter

y - 4 = 2/5(x-(-2))

y-4 = 2/5(x+2)

Hence an equation represents a line that passes through (-2, 4) and has a slope of 2/5 is y-4 = 2/5(x+2)

Learn more on equation of a line here: brainly.com/question/13763238

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3 0
2 years ago
Below is the five-number summary for 144 hikers who recently completed the John Muir Trail (JMT). The variable is the amount of
bearhunter [10]

Answer:

The IQR is given by:

IQR = Q_3 -Q_1 = 28-18= 10

If we want to find any possible outliers we can use the following formulas for the limits:

Lower= Q_1 - 1.5 IQR

Upper= Q_3 + 1.5 IQR

And if we find the lower limt we got:

Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3

Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43

So then the left boundary for this case would be 3 days

Step-by-step explanation:

For this case we have the following 5 number summary from the data of 144 values:

Minimum: 9 days

Q1: 18 days

Median: 21 days

Q3: 28 days

Maximum: 56 days

The IQR is given by:

IQR = Q_3 -Q_1 = 28-18= 10

If we want to find any possible outliers we can use the following formulas for the limits:

Lower= Q_1 - 1.5 IQR

Upper= Q_3 + 1.5 IQR

And if we find the lower limt we got:

Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3

Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43

So then the left boundary for this case would be 3 days

6 0
3 years ago
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