Answer:
1) 6x = 21
2) x + y - 3
3) x/z = y
4) 2-x = p
Step-by-step explanation:
1. The product of a number x and 6 is 21
A product is a multiplication. A product of a and b is a * b.
We then have a product of x and 6, that x * 6, which we write usually in the format 6x.
is 21: that means it's equal to 21....
so 6x = 21.
2. The sum of the quantity x- 3 and y
The sum is an addition. The sum of a and b is a + b.
In this case, the first part is x - 3, the second part is y
So, x - 3 + y, which we usually rewrite as x + y - 3
3. The quotient of x and z is y
A quotient is a division.
So, quotient of x and z is x/z.
x/z = y
4. The difference of 2 and x is p.
A difference is a subtraction.
Difference of 2 and x is 2 - x
2 - x = p
y= 1/10x - 6
Which if you plug in 70 for x, y equals 1.
Rebecca has $1 and Tim has $70, together they have $71.
Given:
The zeros of the polynomial are 
.
Degree = 4
Leading coefficient = 1
To find:
The polynomial.
Solution:
If c is a zero of a polynomial, then (x-c) must be a factor of the polynomial.
Here, -2,4,-5, 5, are zeros of the required polynomial, so (x+2), (x-4), (x+5), (x-5) are factors of required polynomial.
![[\because a^2-b^2=(a-b)(a+b)]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D)
Using distributive property, we get
On combining like terms, we get
Here, the leading coefficient is 1. So, it is the required polynomial.
Therefore, the correct option is E.
When at least one of the factors still has a common factor
