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Flura [38]
3 years ago
5

A PQR = A STU. Find the lengths of the sides PQ, TU, and SU.

Mathematics
1 answer:
Mariana [72]3 years ago
3 0

measure using the object

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Step-by-step explanation:

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David y Angie tienen dos cartulinas iguales. David corta la suya en 3 trozos iguales y Angie la corta en 7 trozos. Los dos usan
Bess [88]

Answer:

(i) David ha empleado \frac{2}{3} de la cartulina.

(ii) Angie ha empleado \frac{2}{7} de la cartulina.

(iii) David ha usado más cartulina.

Step-by-step explanation:

El problema indica que David y Angie emplean una cartulina del mismo tamaño cada uno. David corta la suya en 3 pedazos iguales, mientras que Angie obtiene 7 pedazos iguales. Finalmente, cada uno emplea dos de sus pedazos. A continuación, respondemos a las preguntas del enunciado:

(i) <em>¿Qué fracción de cartulina ha usado David?</em>

La fracción de cartulina empleada por David es igual a los pedazos utilizados divididos por el total de pedazos. Esto es:

x = \frac{2}{3}

David ha empleado \frac{2}{3} de la cartulina.

(ii) <em>¿Qué fracción de cartulina ha usado Angie?</em>

Aplicando el mismo procedimiento del punto anterior, tenemos que:

x = \frac{2}{7}

Angie ha empleado \frac{2}{7} de la cartulina.

(iii) <em>¿Quién ha usado más cartulina?</em>

La persona que ha usado la mayor cantidad de cartulina es aquella que tiene el menor denominador. Por tanto, David ha usado más cartulina.

7 0
3 years ago
A charity is holding a raffle and sells 2000 tickets for $2 each. One ticket will win a grand
777dan777 [17]

Answer:

Lose $1.70 for each ticket you purchase

Step-by-step explanation:

($500 x 1/2000) + ($50 x 2/2000) - $2

$0.25 + $0.05 - $2

-$1.70

4 0
3 years ago
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