Answer:
in steps
Step-by-step explanation:
DE // BC
m∠ADE = m∠ABC and m∠AED = m∠ACB
∴ ΔADE similar to ΔABC
AB/AD = AC/AE
(AD + DB) / AD = (AE + EC) / AE
AD/AD + DB/AD = AE/AE + EC/AE
1 + DB/AD = 1 + EC/AE
DB/AD = EC/AE (AD/DB = AE/EC)
4. Simplify (5xy3)2 Please help
1 answer:
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Answer:
Smaller Number = 10
Larger Number = 33
Step-by-step explanation:
Let the smaller number be "x" and the larger number be "y"
5 TIMES smaller is SUBTRACTED from TWICE larger, the result is 16, we can write:
2y - 5x = 16
and
Larger increased by 3 TIMES SMALLER, result is 63, so we can write:
y + 3x = 63
We can write this in terms of x, as:
y = 63 - 3x
Now we put this in equation 1 and solve for x first:
2y - 5x = 16
Now,
y = 63 - 3x
y = 63 - 3(10)
y = 63 - 30
y = 33
Smaller Number = 10
Larger Number = 33
Answer:
79. [7, 12], [1, 6]
80. The total revenue in the month of May is $11,575
81. The total revenue in the month of November is $4,630
82. Values obtained from the model and actual values are almost the same, so the given model is precise.
Step-by-step explanation:
79.
The domain of a function is the set of x-values that we are allowed to plug into our function.
The graph below represents f(x),
the graph that the domain of the first part of the function is [7,12]. The domain of the second part of the function is [1,6]. The solution is:
80.
1 ≤ 5 ≤ 6, so we'll plug the value 5 in the function f(x) = 0.505x² - 1.47x + 6.3
f(x) = y = (0.505)(5)² - 1.47(5) + 6.3
f(x) = y = (0.505)(25) - 7.35 + 6.3
f(x) = y = 12.625 - 1.05
f(x) = y = 11.575
For x=5 which represents 5th month May, we got y=11.575
Therefore, the total revenue in the month of May is 11.575 thousands dollars, ie 11,575 dollars.
81.
7 ≤ 11 ≤ 12, so we'll plug the value 11 in the function f(x) = -1.97x + 26.3
f(x) = − 1.97(11) + 26.3
= − 21.67 + 26.3
= 4.630.
For x=11 which represents 11th month November, we got y=4.630 Therefore, the total revenue in the month of November is 4.630 thousands dollars, 4,630 dollars.
82.
Values obtained from the model are y=11.575 (x=5) and y=4.630 (x=11). Actual data values are y=11.5 (x=5) and y=4.4 (x=11)
By comparing these values, we can conclude that the model is precise, because these values are almost the same.
Learn more about Piecewise Functions here: brainly.com/question/13882670
