Answer:1) a. Yes, b. , c. Number of tickets= x, d. Total cost = y.
2) a. Yes b. , c. Weight = x, d. Total cost = y.
Step-by-step explanation:
Answer:
9a) 48
b) 48
c) 132
d) 138
e) 42
f) 48
Step-by-step explanation:
Only the first diagram was marked.
Answer:
10 Milk chocolates
8 dark chocolates
6 white chocolates
24 TOTAL
\frac{10}{24} Probability that Hanissa choose a milk chocolate
Now, since she has already eaten one chocolate, then what's left is 23 chocolates.
So, since the second one should be a white chocolate and there are 6 of them, then
\frac{6}{23} - probability of choosing a white chocolate.
Then, multiply,
( \frac{10}{24} )( \frac{6}{23} )= \frac{60}{552} or \frac{5}{46}
Answer: 5/46 or 10.87%
Step-by-step explanation:
Do you have an example problem? I could help you there if you have one :)
Answer:
1 / 3
Step-by-step explanation:
Bag 1 :
Yellow = 3
Green = 2
Red = 1
Total = 3 + 2 +1 = 6
Bag 2 :
Yellow = 3
Green = 3
Red = 3
Total = 3 + 3 + 3 = 9
P(not yellow from bag 1) = (green + red) / total = 3 /6 = 1/2
P(not yellow from bag 2) = (green + red) / total = 6/9 = 2 /3
P(neither is yellow) = 1/2 * 2/3 = 2 / 6 = 1/3