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OleMash [197]
4 years ago
13

Simplify (6.89+14.52) + (-14.52)

Mathematics
2 answers:
Svetach [21]4 years ago
6 0

Answer:

689          

 ——— = 6.89000

 100          

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "14.52" was replaced by "(1452/100)". 3 more similar replacement(s)

Step-by-step explanation:

Step  1  :

           363

Simplify   ———

           25

Equation at the end of step  1  :

  689    1452           363

 (——— +  ————) +  (0 -  ———)

  100    100            25

Step  2  :

           363

Simplify   ———

           25

Equation at the end of step  2  :

  689    363     -363

 (——— +  ———) +  ————

  100    25       25

Step  3  :

           689

Simplify   ———

           100

Equation at the end of step  3  :

  689    363     -363

 (——— +  ———) +  ————

  100    25       25

kogti [31]4 years ago
4 0

Answer:

6.89

Step-by-step explanation:

  6.89

<u>+14.52</u>

 21.41

21.41

<u>-14.52</u>

6.89

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It is not a function because both (2, 2) and (2,−2) have the same x-coordinate. It is a function because both (2, 2) and (2,−2)
olya-2409 [2.1K]

Answer:

It is not a function because both (2,2) and (2,-2) have the same x-coordinate.

Step-by-step explanation:

To be a function for the same x value there should NOT be two different y values.

So, in (2, 2) and (2,-2)

For the same x value 2, there are two different y values 2, -2.

So, this is not a function.

3 0
3 years ago
What is Question I (if m&lt;EBF = 117°, fine m&lt;ABE)​
Natasha_Volkova [10]

Answer:

m∠ABE = 27°

Step-by-step explanation:

* Lets look to the figure to solve the problem

- AC is a line

- Ray BF intersects the line AC at B

- Ray BF ⊥ line AC

∴ ∠ABF and ∠CBF are right angles

∴ m∠ABF = m∠CBF = 90°

- Rays BE and BD intersect the line AC at B

∵ m∠ABE = m∠DBE ⇒ have same symbol on the figure

∴ BE is the bisector of angle ABD

∵ m∠EBF = 117°

∵ m∠EBF = m∠ABE + m∠ABF

∵ m∠ABF = 90°

∴ 117° = m∠ABE + 90°

- Subtract 90 from both sides

∴ m∠ABE = 27°

4 0
4 years ago
Read 2 more answers
M is a degree 3 polynomial with m ( 0 ) = 53.12 and zeros − 4 and 4 i . Find an equation for m with only real coefficients (i.E.
Nitella [24]

Answer:

Therefore the required polynomial is

M(x)=0.83(x³+4x²+16x+64)

Step-by-step explanation:

Given that M is a polynomial of degree 3.

So, it has three zeros.

Let the polynomial be

M(x) =a(x-p)(x-q)(x-r)

The two zeros of the polynomial are -4 and 4i.

Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.

Then,

M(x)= a{x-(-4)}(x-4i){x-(-4i)}

      =a(x+4)(x-4i)(x+4i)

      =a(x+4){x²-(4i)²}      [ applying the formula (a+b)(a-b)=a²-b²]

      =a(x+4)(x²-16i²)

      =a(x+4)(x²+16)      [∵i² = -1]

      =a(x³+4x²+16x+64)

Again given that M(0)= 53.12 . Putting x=0 in the polynomial

53.12 =a(0+4.0+16.0+64)

\Rightarrow a = \frac{53.12}{64}

      =0.83

Therefore the required polynomial is

M(x)=0.83(x³+4x²+16x+64)

5 0
3 years ago
Mai and Tyler work on the equation 2/5 b + 1 = -11 together. Mai’s solution is b= -25 and Tyler’s is b = -28 Here is their work.
alisha [4.7K]

Answer:

<em>I disagree with both solutions. The value of b that will make the expression correct is -30</em>

Step-by-step explanation:

Given the equation solved my Mai and Tyler expressed as:

2/5 b + 1 = -11

We are to check the veracity of the solutions;

2/5 b + 1 = -11

Subtract 1 from both sides of the expression

2/5 b + 1 -1 = -11-1

2/5 b = -12

Cross multiply

2b = -12 * 5

2b = -60

Divide both sides by 2

2b/2 = -60/2

b = -30

<em>Since the solution b = -25 and -28 does not tally with the gotten solution, I disagree with the both solutions</em>

6 0
3 years ago
H(n) = -2n² + 4; Find h(4)<br>A.-28<br>B.68<br>C.28<br>D.-4​
Elena L [17]

Answer:

-28

Step-by-step explanation:

h(4)=-2(4)^2+4

-32+4=-28

7 0
3 years ago
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