Answer:
95.44% of the grasshoppers weigh between 86 grams and 94 grams.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 90 grams and a standard deviation of 2 grams.
This means that ![\mu = 90, \sigma = 2](https://tex.z-dn.net/?f=%5Cmu%20%3D%2090%2C%20%5Csigma%20%3D%202)
What percentage of the grasshoppers weigh between 86 grams and 94 grams?
The proportion is the p-value of Z when X = 94 subtracted by the p-value of Z when X = 86. So
X = 94
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{94 - 90}{2}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B94%20-%2090%7D%7B2%7D)
![Z = 2](https://tex.z-dn.net/?f=Z%20%3D%202)
has a p-value of 0.9772.
X = 86
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{86 - 90}{2}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B86%20-%2090%7D%7B2%7D)
![Z = -2](https://tex.z-dn.net/?f=Z%20%3D%20-2)
has a p-value of 0.0228.
0.9772 - 0.0228 = 0.9544
0.9544*100% = 95.44%
95.44% of the grasshoppers weigh between 86 grams and 94 grams.
I believe Jessica’s rate in miles per hour is 0.9.
Answer:
B. -pi/6
Step-by-step explanation:
Answer:
it will turn out to be a repeating decimal so put a little line over the first 3 to the right of the decimal (517.8333333333)
Step-by-step explanation:
You didn't provide the possible answers, but the smallest length of time will result in the least amount of interest.