Given :
Area of rectangle.
To Find :
The dimensions of a rectangle (in m) with area 1,728 m2 whose perimeter is as small as possible.
Solution :
Let, the dimensions of rectangle is x and y.
Area, A = xy.
x = A/y. ....1)
Perimeter, P = 2( x + y )
Putting value of x in above equation, we get :
For minimum P,
SO, it is a square.
Therefore, the dimensions are .24\sqrt{3}
Hence, this is the required solution.
First you must acknowledge that you are dealing with a line therefore you must write linear equation or linear function in this case.
Linear function has a form of,
Then calculate the slope <em>m</em> using the coordinates of two points. Let say <em>A(x1, y1)</em> and <em>B(x2, y2)</em>,
Now pick a point either <em>A</em> or <em>B</em> and insert coordinates of either one of them in the linear equation also insert the slope you just calculated, I will pick point <em>A</em>.
From here you solve the equation for n,
So you have slope <em>m</em> and variable <em>n</em> therefore you can write down the equation of the line,
Hope this helps.
r3t40