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Serga [27]
3 years ago
5

Help plzzz someone solve it i need help

Mathematics
1 answer:
nekit [7.7K]3 years ago
4 0
19° hope this helped!
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Jordan invests $9,500 into an account that earns 3.25% annual interest. How much will
balandron [24]

The amount of money that Jordan will earn at the end of 10 years = $12,587.5

<h3>Calculation of compounded interests</h3>

The principal amount invested(P) = $9,500

The annual compounded daily interest rate(R) of the account = 3.25%

The time given (T) = 10 years

Simple interest (SI) = P×T × R/100

SI = 9,500×10×3.25/100

SI= 308750/100

SI= $3087.50

Therefore the total amount that would be in the account after 10 years = $9,500 + $3,087.50

= $12,587.5

Learn more about compound interest here:

brainly.com/question/24924853

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Each finger width is about 10 miles how many miles will he count if he uses 7 finger widths
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Answer:

7 Miles is the answer.

Step-by-step explanation:

10*7=70.

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3 years ago
A bakery sold 16 apple pie on Saturday they sold 4 more apple pies on Sunday than they did on Saturday how many apple pies did t
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Answer:

20 apple pies

Step-by-step explanation:

On Saturday they sold 16, while on Sunday they sold 4 more.

16+4 = 20.

20 apple pies.

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Yes u only we're it if itsnows
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John, Sally, and Natalie would all like to save some money. John decides that it would be best to save money in a jar in his clo
Radda [10]

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2) y=100x+300

Part 3) \$12,300

Part 4) Is a exponential growth function

Part 5) A=6,000(1.07)^{t}  

Part 6) \$11,802.91  

Part 7) Is a exponential growth function

Part 8) A=5,000(e)^{0.10t}    or  A=5,000(1.1052)^{t}  

Part 9)  \$13,591.41

Part 10) Natalie has the most money after 10 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

y=mx+b

The slope is equal to

m=\$100\ per\ month

The y-intercept or initial value is

b=\$300

so

y=100x+300

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

y=100x+300

see part 1)

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

so

10 years=10(12)=120 months

For x=120 months

substitute in the linear equation

y=100(120)+300=\$12,300

Part 4) What type of exponential model is Sally’s situation?

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

P=\$6,000\\ r=7\%=0.07\\n=1  

substitute in the formula above

A=6,000(1+\frac{0.07}{1})^{1*t}  

A=6,000(1.07)^{t}  

therefore

Is a exponential growth function

Part 5) Write the model equation for Sally’s situation

A=6,000(1.07)^{t}  

see the Part 4)

Part 6) How much money will Sally have after 10 years?

For t=10 years

substitute  the value of t in the exponential growth function

A=6,000(1.07)^{10}=\$11,802.91  

Part 7) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

P=\$5,000\\r=10\%=0.10  

substitute in the formula above

A=5,000(e)^{0.10t}  

Applying property of exponents

A=5,000(1.1052)^{t}  

therefore

Is a exponential growth function

Part 8) Write the model equation for Natalie’s situation

A=5,000(e)^{0.10t}    or  A=5,000(1.1052)^{t}

see Part 7)

Part 9) How much money will Natalie have after 10 years?

For t=10 years

substitute

A=5,000(e)^{0.10*10}=\$13,591.41

Part 10) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

4 0
3 years ago
Read 2 more answers
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