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2 years ago

Pleaseeeee helppppp meeeee

Mathematics

1 answer:

umka2103 [35]2 years ago

5 0

Answer:

NY or MZ

Step-by-step explanation:

they are both outside of the parallel lines and on opposite sides of the transverse line

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Please answer this for me SHOW WORK 60 points and brainliest

Sliva [168]

Answer:

OMG YES THANKS IF U EVER COMMENT ON MY QUESTION I WILL KEEP PUTTING RANDOME STUFF MWAH

Step-by-step explanation:

3 0

2 years ago

Please answer the question attached in the pic

pantera1 [17]

Answer:

(25)^2*(9)^2*(4squreroot2)^2*(7squreroot2)^2

Step-by-step explanation:

5^4*3^3*2^5*343

=(25)^2*(9)^2*(4squreroot2)^2*(7squreroot2)^2

5 0

2 years ago

Use the identity (x+y)(x−y)=x2−y2 to find the difference of two numbers if the sum of the numbers is 12 and the difference of th

Natalka [10]

Answer:

The difference of two numbers using identity $(x+y)(x-y)=x^2-y^2$ is 4.

Step-by-step explanation:

Given: The sum of the numbers is 12 and the difference of the squares of the numbers is 48.

To find the difference of two numbers using identity $(x+y)(x-y)=x^2-y^2$

Let the two numbers be a and b, then

Given that the sum of the numbers is 12

that is a + b = 12 .........(1)

Also, given the difference of the squares of the numbers is 48.

that is $a^2-b^2=48$ ..........(2)

Using given identity $(x+y)(x-y)=x^2-y^2$

We have $(a+b)(a-b)=a^2-b^2$

Substitute the known values, we have,

$12(a-b)=48$

Divide both side 12 , we have,

$(a-b)=4$

Thus, the difference of two numbers using identity $(x+y)(x-y)=x^2-y^2$ is 4.

8 0

3 years ago

Read 2 more answers

Factor the following quadratic equation; <br><img src="https://tex.z-dn.net/?f=12%20%7Bx%7D%5E%7B2%7D%20%20%2B%2022x%20-%2014" i

Bogdan [553]

Answer:

2(3x + 7)(2x - 1)

Step-by-step explanation:

You can see it a little easier if you take out a common factor of 2

2(6x^2 + 11x - 7)

The 6 leaves you with a lot of factors, the 7 does not. It only has 2 factors.

Let 6 factor into 2 and 3 and the 7 into 7 and 1

2(3x - 1 )(2x + 7)

Now remove the brackets.

2(6x^2 + 21x - 2x - 7) This obviously does not work but we'll combine like terms anyway.

2(6x^2 + 19x - 7)

So we'll try it again

2(3x + 7)(2x - 1)

2(6x^2 + 14x - 3x - 7) Looks like we have it.

2(6x^2 + 11x - 7)

So the right factors are

2(3x + 7)(2x - 1)

5 0

3 years ago

Find the solutions of the equation f(x)=(x+3)(x-b)

Lapatulllka [165]

The answer for this solution is D
-3 and b

5 0

2 years ago