A. False. The data is quantitative because we're dealing with numeric values instead of things like names, colors, etc.
B. False. The row categories are "students" and "teachers"
C. True. This value (2) is in the "teachers" row and "does not wear glasses" column.
D. False. The value 32 represents the number of students who wear glasses. See row1, column1
E. True. Look at the last value of the "teachers" row.
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In summary, the answers are: C and E
Answer:
30 lb/pounds
Step-by-step explanation:
used an online conversion
Answer:
This contradicts the Mean Value Theorem since there exists a c on (1, 7) such that f '(c) = f(7) − f(1) (7 − 1) , but f is not continuous at x = 3
Step-by-step explanation:
The given function is

When we differentiate this function with respect to x, we get;

We want to find all values of c in (1,7) such that f(7) − f(1) = f '(c)(7 − 1)
This implies that;




![c-3=\sqrt[3]{63.15789}](https://tex.z-dn.net/?f=c-3%3D%5Csqrt%5B3%5D%7B63.15789%7D)
![c=3+\sqrt[3]{63.15789}](https://tex.z-dn.net/?f=c%3D3%2B%5Csqrt%5B3%5D%7B63.15789%7D)

If this function satisfies the Mean Value Theorem, then f must be continuous on [1,7] and differentiable on (1,7).
But f is not continuous at x=3, hence this hypothesis of the Mean Value Theorem is contradicted.