You should write numbers in as many ways as you possibly can to make new connections in your brain. Knowing how to write numbers in many different ways can help you solve complex problems more easily. Doing this can also reinforce the mathematical principles and logic you have memorised.
Writing one in many different ways:
1=1/1=2/2=3/3=4/4=(-1)/(-1)=(-2)/(-2)
=1.0=1.00=1.000=(1/2)+(1/2)=(1/3)+(1/3)+(1/3)
=(1/4)+(1/4)+(1/4)+(1/4)
Writing a half in many different ways:
1/2=(1/4)+(1/4)=(1/6)+(1/6)+(1/6)
=(1/8)+(1/8)+(1/8)+(1/8)=4*(1/8)
=2/4=3/6=4/8=5/10=0.5=0.50
etc...etc...
Answer: (a) P(no A) = 0.935
(b) P(A and B and C) = 0.0005
(c) P(D or F) = 0.379
(d) P(A or B) = 0.31
Step-by-step explanation: <u>Pareto</u> <u>Chart</u> demonstrates a relationship between two quantities, in a way that a relative change in one results in a change in the other.
The Pareto chart below shows the number of people and which category they qualified each public school.
(a) The probability of a person not giving an A is the difference between total probability (1) and probability of giving an A:
P(no A) = 
P(no A) = 1 - 0.065
P(no A) = 0.935
b) Probability of a grade better than D, is the product of the probabilities of an A, an B and an C:
P(A and B and C) = 
P(A and B and C) = 
P(A and B and C) = 0.0005
c) Probability of an D or an F is the sum of probabilities of an D and of an F:
P(D or F) = 
P(D or F) = 
P(D or F) = 0.379
d) Probability of an A or B is also the sum of probabilities of an A and of an B:
P(A or B) = 
P(A or B) = 
P(A or B) = 0.31
Answer:
do we do the x veriable as the numerator? if so it's not a or c if not vice versa
Step-by-step explanation:
The formula is
a^3 - b^2 = (a - b)(a^2 + ab + b^2) so plugging in the given values:-
a = cube root of 125 = 5 and b = cube root of 27 = 3 , we get:-
125 - 27 = (5 - 3)(5^2 + 5*3 + 3^2)
= 2 * 49
= 98 answer