Answer:
xy^(2)z^(6)
Step-by-step explanation:
i hope that helps you :)
Answer:
Step-by-step explanation:
a) -3
b) 5
c) -2
d) -6
Answer:
1) b and m
2) m∠8=m∠6
3) 160°
4)x=60°
Step-by-step explanation:
1) all straight lines sum to 180°
subtract the angles given from 180°
the other angle for b is 25°, while the other angle for m is 155°
so we can see that the angles for both lines are the same, hence they are parallel.
2) ∠8 should be the same as ∠6, ∠10 should be the same as ∠3, ∠7 same as ∠5 and ∠9 same as ∠4
in the options we are only given '∠8 should be the same as ∠6' as the correct answer, so we take that.
3) from the image we can see that both horizontal lines are parallel to each other, so both angles on the lines should be same, so ∠CET would be (2x-16)°
(2x-16)°+(7x+20)°=180°
we get x=20(nearest whole number)
∠CED=7x+20=7(20)+20=160°
4) since we need to show that they are parallel,
(2x+30)°=(4x-90)°
2x-4x=-90-30
-2x=-120
x=60
we then plug the x value into the two equations, in which we get 150° for both the angles [2(60)+30=4(60)-90] ⇒ (150=150)
I hope u understand it the way I put it.
(-2,3). When rotating a point 90 degrees counterclockwise about the origin our point A(x,y) becomes A'(-y,x).
Answer:
The length of segment QM' = 6
Step-by-step explanation:
Given:
Q is the center of dilation
Pre-image (original image) = segment LM
New image = segment L'M'
The length of LQ = 4
The length of QM = 3
The length of LL' = 4
The original image was dilated with scale factor = 2
QM' = ?
To determine segment QM', first we would draw the diagram obtained from the given information.
Find attached the diagram
When a figure is dilated, we would have similar shape in thus cars similar triangles.
Segment L'M' = scale factor × length of LM
Let LM = x
L'M' = 2x
Using similar triangles theorem, ratio of their corresponding sides are equal.
QM/LM = QM'/L'M'
3/x = QM'/2x
6x = QM' × x
Q'M' = 6
The length of segment QM' = 6
