There is a little-known theorem to solve this problem.
The theorem says that
In a triangle, the angle bisector cuts the opposite side into two segments in the ratio of the respective sides lengths.
See the attached triangles for cases 1 and 2. Let x be the length of the third side.
Case 1:
Segment 5cm is adjacent to the 7.6cm side, then
x/7.6=3/5 => x=7.6*3/5=
4.56 cm
Case 2:
Segment 3cm is adjacent to the 7.6 cm side, then
x/7.6=5/3 => x=7.6*5/3=
12.67 cmThe theorem can be proved by considering the sine rule on the adjacent triangles ADC and BDC with the common side CD and equal angles ACD and DCB.
Answer:
42+34+14=90
Step-by-step explanation:
42 people are male
34 people study biology
14 males study biology (thats both)
Answer:
4 minutes
Step-by-step explanation:
make equation
0.25+(0.15x)= 0.85
solve for x
0.15x= 0.60
x=4
Answer:
First solve the equation:
6x^2 + 8x -28 = 2x^2 + 4
=> 6x^2 - 2x^2 + 8x - 28 -4 = 0 => 4x^2 + 8x - 32 = 0
Extract common factor 4:
=> 4[x^2 + 2x - 8] = 0
Now factor the polynomial:
4(x + 4) (x - 2) = 0
=> the solutions are x + 4 = 0 => x = -4, and x - 2 = 0 => x = 2.
So the answer is the option B: 4(x + 4)(x - 2); {-4, 2}
HOPE THIS HELPS! :D
Answer:
First term a = 3
Sum of first 20 term = 440
Step-by-step explanation:
Given:
8th term of AP = 17
12th term of AP = 25
Find:
First term a
Sum of first 20 term
Computation:
8th term of AP = 17
a + 7d = 17 ....... EQ1
12th term of AP = 25
a + 11d = 25 ...... EQ2
From EQ1 and EQ2
4d = 8
d = 2
a + 7d = 17
a + 7(2) = 17
First term a = 3
Sum of first 20 term
Sn = [n/2][2a + (n-1)d]
S20 = [20/2][(2)(3) + (20-1)2]
S20 = [10][(6) + 38]
S20 = [10][44]
S20 = 440
Sum of first 20 term = 440