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sashaice [31]
3 years ago
7

The greatest common factor of each term in the expression 20 x minus 16 x y is 4x. Which choice shows the expression written as

a product?
Mathematics
1 answer:
Nadusha1986 [10]3 years ago
4 0

Answer:

20x-16xy=4x

Step-by-step explanation:

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Situation:
Arturiano [62]

Answer:

t = 6162  years

Step-by-step explanation:

Apparently you are asked to use the constant k = 0.0001 instead of the most common 0.00012. We'll answer the problem using such number you typed, but make sure that there is no omission in your typing.

The equation to use is that for carbon decay:

N(t)=N_0\,e^{-0.0001\,\,t}

If the skull contains 54% of its original amount of C14, then that means that :

N(t)=0.54 \,\,N_0

we use this to solve for the time (t) in our equation:

0.54\,\,N_0=N_0\,e^{-0.0001\,\,t}\\\frac{0.54\,\,N_0}{N_0}=e^{-0.0001\,\,t}\\0.54=e^{-0.0001\,\,t}\\ln(0.54)=-0.0001\,\,t\\t=\frac{ln(0.54)}{-0.0001} \\t=6161.86\,\,years

which rounded to the nearest year as requested gives :

t = 6162  years

8 0
3 years ago
A school is having a big basket ball game this weekend against its rival school. They sold all their 150 available tickets and c
qaws [65]

Answer:

is this a multiple choice question?? it would be very hard to figure out without the answer choices

Step-by-step explanation:

8 0
3 years ago
When a number is increased by 5% the result is 25 what is the original number to the nearest 10th
lbvjy [14]
The original number to the nearest tenth is 23.8
3 0
2 years ago
1.23/16 prosto do matury potrzebuję pomocy!
Anestetic [448]
1.23/16 = 0.076875 . totally answer
7 0
2 years ago
Point f lies between points g and m. gf =12x+4, fm=16 and gm =16x what is the value of x
Flura [38]

\underset{\leftarrow \qquad \text{\LARGE 16x}\qquad \to }{\stackrel{12x + 4}{G\rule[0.35em]{10em}{0.25pt}} F\stackrel{16}{\rule[0.35em]{16em}{0.25pt}M}} \\\\\\ \stackrel{GF}{12x+4} ~~ + ~~ \stackrel{FM}{16} ~~ = ~~ \stackrel{GM }{16x}\qquad \implies 12x+20=16x \\\\\\ 20=4x\implies \cfrac{20}{4}=x\implies 5=x

8 0
1 year ago
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