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2 years ago

Utilize graphing to find the solution to

Mathematics

1 answer:

Llana [10]2 years ago

7 0

Answer:

(4, -3)

Step-by-step explanation:

To solve this with graphing all you need to do is enter both equations in a graphing calculator (you can use desmos online) and then find the point where both lines intersect.

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A parabola intersects at x-axis at x= 2 and x= 6. What is the x-coordinate of the parabolas vertex?

charle [14.2K]

Answer:

x = 4

Step-by-step explanation:

The vertex is on the line of symmetry. The zeros are located equidistant from the line of symmetry, which is ...

x = (2 + 6)/2 = 4

The x-coordinate of the vertex is x=4.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7Ba%5E2%20-2a-b%5E2%3D0%7D%20%5Catop%20%7B2b%2B2ab%3D0%7D%7D%20%5Cright

oksian1 [2.3K]

Given :-

a² - 2a - b² = 0
2b + 2ab = 0

To find :-

Value of a and b .

Solution :-

Taking second equation:-

2b + 2ab = 0
2b ( 1 + a ) = 0
2b = 0 or (1+a) = 0
b = 0 , a = -1

Substitute in first equation :-

a² - 2a - b² = 0

When b = 0 ,

a² - 2a - 0² = 0
a² - a = 0
a( a -1) =0
a = 0 , 1

When a = -1 ,

(-1)² - 2*(-1) - b² = 0
1 + 2 - b² = 0
b² = 3
b = ±√3

Answer :-

a = 0,1 ; b = 0
a = -1 , b = ±√3

8 0

2 years ago

Find the probability of showing the product 6

Klio2033 [76]

Answer:

The probability is 1/6.

Step-by-step explanation:

7 0

2 years ago

Whats the roots of the following three problems:

klemol [59]

QUESTION 1

The given function is

$f(x)=\frac{(x-3)(x-1)}{(x-1)(x+2)}$

We simplify to get;

$f(x)=\frac{x-3}{x+2}$

This function is equal to zero when $x-3=0$

$\Rightarrow x=3$

QUESTION 2

The given function is

$f(x)=\frac{5x^2-10x+5}{2x^2-5x+3}$

$f(x)=\frac{5(x^2-2x+1)}{2x^2-5x+3}$

We factor to get;

$f(x)=\frac{5(x-1)^2}{(2x-3)(x-1)}$

$f(x)=\frac{5(x-1)}{(2x-3)}$

This function equals zero when

$5(x-1)=0$

$x=1$

QUESTION 3

The given function is

$f(x)=\frac{x^3-8}{x^2-6x+8}$

We factor to get,

$f(x)=\frac{(x-2)(x^2+2x+4)}{(x-2)(x+4)}$

$f(x)=\frac{x^2+2x+4}{x+4}$

The function equals zero when $x^2+2x+4=0$

$D=b^2-4ac$

$D=2^2-4(1)(4)$

$D=-12$

Hence the equation has no real roots.

The complex roots are

$x=-\sqrt{3}i-1$ or $x=-1+\sqrt{3}i$

4 0

2 years ago

An item is originally marked $35.99. The store marks the price down to $28.59. What is the PERCENT MARKDOWN of the item?

Alja [10]

Answer: 125.8832

Step-by-step explanation:

(35.99/28.59)*100=125.8832

4 0

2 years ago