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matrenka [14]
3 years ago
7

What is 578 x 6,937, please

Mathematics
2 answers:
Harman [31]3 years ago
8 0
The answer is (4,009,586)

578*6,937= 4,009,586
kati45 [8]3 years ago
7 0
<span>400,958,6 Hope this helps!</span>
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prohojiy [21]
The answer to this is d.) 1. This is because any number that is raised to the zero power is 1. 
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3 years ago
Is this right? I feel like I’m wrong.
Arisa [49]

Answer:

no I believe you are correct

Hope This Helps! Have A Nice Day!!

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4 years ago
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What is the <br> Area of Circles:<br> Shaded area:
Rudiy27

Answer:

each square takes up a 10 by 10 square is you divide it into to four pieces then you use the formula for area of a circle

Step-by-step explanation:

1) 10 x 10

Find the diameter which is 5

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19.625

at that 4 times

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6 0
2 years ago
The functions f and g are differentiable for all real numbers x. The table below gives values for the functions and their first
sertanlavr [38]

Answer:

13/9

y =-22x+32

Step-by-step explanation:

Given that the functions f and g are differentiable for all real numbers x. The table below gives values for the functions and their first derivatives at selected values of x.

x f(x) f'(x) g(x) g'(x)

1 4 -3 5 2

2 -3 -1 4 6

3 π 8 -1 4

4 -5 unknown 0 3

a) h(x) = \frac{f(x)}{g(x)} \\h'(x) = \frac{g(x)f'(x)-f(x)g'(x)}{(g(x))^2}

(using quotient rule)

Substitute 1 for x

h'(1) = \frac{g(1)f'(1)-f(1)g'(1)}{(g(1))^2}\\=\frac{9-(-4)}{9} \\=\frac{13}{9}

b) r(x) = f(x) g(x)\\r'(x) = f(x) g'(x)+g(x)f'(x)

when x =2, r(x) = r(2) = f(2) g(2) = -12

point of contact is (2,-12)

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Using point slope form, tangent is

y+12 = -22(x-2)\\y = -22x +32

7 0
4 years ago
How do i do this<br> 5e+4&lt;3e-6
Nonamiya [84]

Answer:

e < -5

Step-by-step explanation:

5e + 4 < 3e - 6

Subtract 3e from the right side

2e + 4 < -6

Subtract 4 from the left side

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Divide both sides by 2

e < -5

6 0
3 years ago
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