Answer:
B. (-3, 5)
Step-by-step explanation:
Try them.
You can eliminate choice A because y=-3 is not greater than -2.
You can eliminate choices C and D because the sum of x and y is not less than 4.
Point (-3, 5) satisfies both inequalities. (Choice B)
Answer:
Step-by-step explanation:
o What proportion of normal distribution corresponds to z-scores < z = 1.00? o What is the probability of selecting a z-score less than z = 1.00? (A). (B). (C).
Answer:
6a^2+ 2bc-2c^1/3 <u>= 162</u>
Step-by-step explanation:
![\rm = 6 + 162 - 2 ( \sqrt[3]{27} )](https://tex.z-dn.net/?f=%20%5Crm%20%20%3D%206%20%2B%20162%20-%202%20%28%20%5Csqrt%5B3%5D%7B27%7D%20%29)
Answer:
a=16400 feet
Step-by-step explanation:
t = -0.0035 a +g
-17.40 = -0.0035 a+40
-17.40-40=-0.0035a+40-40
-57.40=-0.0035a
a = -57.40/-0.0035
a=16400 feet
So you can do this multiple ways, I'll do this the way that I think makes sense the l most easily.
Cos (0) = 1
Cos (pi/2)=0
Cos (pi) =-1
Cos (3pi/2)=0
Cos (2pi)=1
Now if you multiply the inside by 4, the graph oscillates more violently (goes up and down more in a shorter period).
But you can always reduce it.
Cos (0)= 1
Cos (4pi/2) = cos (2pi)=1
Cos (4pi) =Cos (2pi) =1 (Any multiple of 2pi ==1)
etc...
the pattern is that every half pi increase is now a full period as apposed to just a quarter of one. That's in theory.
Now that you know that, the identities of Cosine are another beast, but mathematically.
You have.
Cos (2×2t) = Cos^2 (2t)-Sin^2 (2t)
Sin^2 (t)=-Cos^2 (t)+1..... (all A^2+B^2=C^2)
Cos (2×2t) = Cos^2 (t)-(-Cos^2 (t)+1)
Cos (2×2t)= 2Cos^2 (2t) - 1
2Cos^2 (2t) -1= 2 (Cos^2(t)-Sin^2(t))^2 -1
(same thing as above but done twice because it's cos ^2 now)
convert sin^2
2Cos^2 (2t)-1 =2 (Cos^2 (t)+Cos^2 (t)-1)^2 -1
2 (2Cos^2(t)-1)^2 -1
2 (2Cos^2 (t)-1)(2Cos^2 (t)-1)-1
2 (4Cos^4 (t) - 2 (2Cos^2 (t))+1)-1
Distribute
8Cos^4 (t) -8Cos^2 (t) +1
Cos (4t) =8Cos^4-8Cos^2 (t)+-1
