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Dima020 [189]
3 years ago
5

Please Help!!!!!! Use what you've learned today about the sum of the interior angles of triangles and quadrilaterals to determin

e the measure of ALL unknown angles in the figure below.​

Mathematics
1 answer:
sveta [45]3 years ago
6 0

Answer:

m = 116

x = 24

y = 76

z = 40

Step-by-step explanation:

For startes the interior angles of triangles always add up to 180 degrees.

That means....

73 + 83 + x = 180

z + m + x = 180

z + y + 64 = 180

Another important fact is that two angles that are intersected by a line in the case 64 and m always add up to 180 degrees.

So m + 64 = 180

Let's start with 73 + 83 + x = 180

If you add 73 and 83 you get 156

x + 156 = 180 then subtract 156 from both sides and

x = 24

Then use m + 64 = 180 subtract 64 from both sides and

m = 116

z + m + x = 180 become

z + 116 + 24 = 180

Add 116 and 24 and you get 140

z + 140 = 180 subtract 140 from both sides and

z = 40

Check to make sure m + x + z = 180

24 + 40 + 116 = 180

z + y + 64 = 180 becomes

y + 40 + 64 = 180

40 + 64 = 104 so

y + 104 = 180 subtract 104 from both sides and

y = 76

Congratulations you have found all of the angles!

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Prove that 2n^3 + 3n^2 + n is divisible by 6 for every integer n > 1 by mathematical induction. (7 marks)
notka56 [123]

Answer:

The answer is True

Step-by-step explanation:

A <em>mathematical induction</em> consists in only 2 steps:  

<u>First step</u>: Show the proposition is true for the first one valid integer number.

<u>Second step</u>: Show that if any one is true then the next one is true  

Finally, if first step and second step are true, then the complete proposition is true.

So, given 2*n^3+3*n^2+n

First step: using and replacing n=2 (the first valid integer number >1)

2*(2)^3 +3*(2)^2+2=30

\frac{30}{6} =5

As the result is an integer number, so the first step is true.

Second step: using any next number, n+1, let it replace

2*(n+1)^3+3*(n+1)^2+(n+1)\\2*(n^3+3*n^2+3*n+1)+3*(n^2+2*n+1)^2+(n+1)\\2*n^3+6*n^2+6*n+2+3*n^2+6*n+3+n+1\\(2*n^3+3*n^2+n)+(6*n^2+12*n+6)

As the First step is true, we know that

2*n^3+3*n^2+n=6*k,

So let it replace in the previous expression

6*k+6*(n^2+2*n+1)\\6*[k+(n^2+2*n+1)]

Finally

\frac{6*[k+(n^2+2*n+1)]}{6} =k+(n^2+2*n+1)

where the last expression is an integer number

So the second step is true, and the complete proposition is True

5 0
3 years ago
A and B are vertical angles. If m A = (3x+3)° and m B= (4x-8)°, then find the value of x.
iogann1982 [59]

Answer: x=11

Step-by-step explanation:

First, since angle A and angle B are vertical angles, that means that they are congruent. If they are congruent, then the m of angle A equals the measure of angle B. So, (3x+3)=(4x-8). Simplify using algebra so that in the end, you will find that x=11.

3x+3=4x-8

3=x-8

11=x

6 0
3 years ago
PLEASE HELP ASAP!!!!!
Gelneren [198K]

Answer:

The correct answer is 5

3 0
3 years ago
Read 2 more answers
I'll pick brainiest. Please help me!! Answer as best as you can. THANK YOU!!
rodikova [14]

The volume of the cube is 54.87 but rounded to the nearest tenth is 54.9

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5 0
3 years ago
A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 340 babies were​ born, a
Bas_tet [7]

Answer:

The 99% confidence interval estimate of the percentage of girls born is (0.8, 0.9).

b)Yes, the proportion of girls is significantly different from 0.5.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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For this problem, we have that:

In the study 340 babies were​ born, and 289 of them were girls. This means that n = 340, \pi = \frac{289}{340} = 0.85

Use the sample data to construct a 99​% confidence interval estimate of the percentage of girls born.

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{340}} = 0.85 - 2.575\sqrt{\frac{0.85*0.15}{400}} = 0.80

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{340}} = 0.85 + 2.575\sqrt{\frac{0.85*0.15}{400}} = 0.90

The 99% confidence interval estimate of the percentage of girls born is (0.8, 0.9).

Does the method appear to be ​effective?

b)Yes, the proportion of girls is significantly different from 0.5.

4 0
3 years ago
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